[Math Revolution GMAT math practice question]
How many perfect squares lie between 2^4 and 2^8, inclusive?
A. 12
B. 13
C. 15
D. 18
E. 20
How many perfect squares lie between 2^4 and 2^8, inclusive?
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- Max@Math Revolution
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$${2^4} \le {M^2} \le {2^8}\,\,,\,\,\,M\,\,{\mathop{\rm int}} \,\,\,\mathop \ge \limits^{{\rm{WLOG}}} \,\,\,0\,\,\,\,\,\,\,\,\left( * \right)\,\,\,\,\,\,\,\,\,\,\,\left[ {\,{\rm{WLOG}}\,\,{\rm{ = }}\,\,{\rm{without}}\,\,{\rm{loss}}\,\,{\rm{of}}\,\,{\rm{generality}}\,} \right]$$Max@Math Revolution wrote:[Math Revolution GMAT math practice question]
How many perfect squares lie between 2^4 and 2^8, inclusive?
A. 12
B. 13
C. 15
D. 18
E. 20
$$?\,\,\,:\,\,\,\# \,\,\,{\rm{of}}\,\,{\rm{possibilities}}\,\,{\rm{for}}\,\,\left( * \right)$$
$$\sqrt {{2^4}} \le \sqrt {{M^2}} \le \sqrt {{2^8}} \,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,4 = {2^2}\,\,\,\mathop \le \limits^{M\,\, \ge \,\,0} M\,\,\, \le {2^4} = 16\,\,\,\,\,\,\,\mathop \Rightarrow \limits^{{\rm{fingers}}\,\,{\rm{technique}}} \,\,\,\,\,\,\,? = 16 - 4 + 1 = 13$$
This solution follows the notations and rationale taught in the GMATH method.
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Fabio.
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First rewrite 2^4 and 2^8 as SQUARES of integers (aka perfect squares)Max@Math Revolution wrote:[Math Revolution GMAT math practice question]
How many perfect squares lie FROM 2^4 TO 2^8, inclusive?
A. 12
B. 13
C. 15
D. 18
E. 20
2^4 = (2²)² = 4²
2^8 = (2^4)² = 16²
So, we want to find the number of perfect squares FROM 4² to 16² inclusive
Let's list them: 4², 5², 6², 7², 8², 9², 10², 11², 12², 13², 14², 15², and 16²
There are 13 such perfect squares
Answer: B
Cheers,
Brent
- Max@Math Revolution
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=>
We need to count the number of integers n satisfying 2^4 ≤ n^2 ≤ 2^8 or 2^2 ≤ n ≤ 2^4.
The number of integers satisfying 2^2 ≤ n ≤ 2^4 is 2^4 - 2^2 + 1 = 16 - 4 + 1 = 13.
Therefore, the answer is B.
Answer: B
We need to count the number of integers n satisfying 2^4 ≤ n^2 ≤ 2^8 or 2^2 ≤ n ≤ 2^4.
The number of integers satisfying 2^2 ≤ n ≤ 2^4 is 2^4 - 2^2 + 1 = 16 - 4 + 1 = 13.
Therefore, the answer is B.
Answer: B
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2^4 = 16 and 2^8 = 256.Max@Math Revolution wrote:[Math Revolution GMAT math practice question]
How many perfect squares lie between 2^4 and 2^8, inclusive?
A. 12
B. 13
C. 15
D. 18
E. 20
Since 2^4 = 4^2 and since 2^8 = 16^2, we see that there are 16 - 4 + 1 = 13 perfect squares lie between 2^4 and 2^8, inclusive.
If this is not clear, notice that the perfect squares between 4^2 and 16^2 must be: 5^2, 6^2, 7^2, ... , 13^2, 14^2, and 15^2, for a total of 13 perfect squares.
Answer: B
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