• NEW! FREE Beat The GMAT Quizzes  Hundreds of Questions Highly Detailed Reporting Expert Explanations
• 7 CATs FREE!
If you earn 100 Forum Points

Engage in the Beat The GMAT forums to earn
100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote How many blueberries tagged by: Brent@GMATPrepNow This topic has 4 expert replies and 1 member reply Hi Need help answering the attached. Thanks Attachments This post contains an attachment. You must be logged in to download/view this file. Please login or register as a user. GMAT/MBA Expert GMAT Instructor Joined 25 May 2010 Posted: 15353 messages Followed by: 1864 members Upvotes: 13060 GMAT Score: 790 Quote: Danny has boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25, and the difference between the total number of strawberries and the total number of blueberries would increase by 95. Each blue box contains how many blueberries? 35 40 45 50 60 Let S = the number of strawberries in each box of strawberries and B = the number of blueberries in each box of blueberries. Let Danny start with ONE BOX OF STRAWBERRIES and ONE BOX OF BLUEBERRIES. Thus: Original total number of berries = S+B. Original difference between the total number of strawberries and the total number of blueberries = S-B. Danny disposed of one blue box for one additional red box. After the blue box is exchanged for a second red box, the result is TWO BOXES of strawberries and NO BLUEBERRIES. Thus: New total number of berries = 2S + 0B = 2S. New difference between the total number of strawberries and the total number of blueberries = 2S - 0B = 2S. The total number of berries (of both kinds) would increase by 25. Since the new total is 25 more than the original total, we get: 2S = (S+B) + 25 S = B+25. The difference between the total number of strawberries and the total number of blueberries would increase by 95. Since the new difference is 95 more than the original difference, we get: 2S = (S-B) + 95 S = -B+95 Since S = B+25 and S =-B+95, the two expressions in red are EQUAL: B+25 = -B+95 2B = 70 B = 35. The correct answer is A. _________________ Mitch Hunt Private Tutor for the GMAT and GRE GMATGuruNY@gmail.com If you find one of my posts helpful, please take a moment to click on the "UPVOTE" icon. Available for tutoring in NYC and long-distance. For more information, please email me at GMATGuruNY@gmail.com. Student Review #1 Student Review #2 Student Review #3 Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now. GMAT/MBA Expert GMAT Instructor Joined 08 Dec 2008 Posted: 12985 messages Followed by: 1249 members Upvotes: 5254 GMAT Score: 770 Quote: Danny has boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25, and the difference between the total number of strawberries and the total number of blueberries would increase by 95. Each blue box contains how many blueberries? 35 40 45 50 60 Let B = number of blueberries PER BOX Let S = number of strawberries PER BOX If Danny disposed of one blue box for one additional red box, the TOTAL number of berries (of both kinds) would increase by 25 So, S - B = 25 Here's why. Let's pretend there is only ONE blue box and ONE red box. So, the TOTAL number of berries = B + S If we remove a blue box and add a red box, the TOTAL number of berries = 2S We're told that the TOTAL DECREASES by 25. So, we can write: B + S + 25 = 2S Rearrange to get: S - B = 25 If Danny disposed of one blue box for one additional red box, the DIFFERENCE between the total number of strawberries and the total number of blueberries would increase by 95 So, S + B = 95 Here's why. If we REMOVE a blue box, the difference is INCREASED by B If we ADD a red box, the difference is INCREASED by S So, the net effect here is increasing the difference by S + B In other words, S + B = 95 We now have the system: S + B = 95 S - B = 25 SUBTRACT the bottom equation from the top equation to get: 2B = 70 Solve to get B = 35 Answer: A Cheers, Brent _________________ Brent Hanneson – Creator of GMATPrepNow.com Use my video course along with Sign up for free Question of the Day emails And check out all of these free resources GMAT Prep Now's comprehensive video course can be used in conjunction with Beat The GMAT’s FREE 60-Day Study Guide and reach your target score in 2 months! Master | Next Rank: 500 Posts Joined 07 Jun 2014 Posted: 126 messages Upvotes: 3 Hi Mitch, The method I followed took me nearly 4 min.Can u pl suggest a quicker method or make it easier to understand? Sandip. GMAT/MBA Expert GMAT Instructor Joined 25 May 2010 Posted: 15353 messages Followed by: 1864 members Upvotes: 13060 GMAT Score: 790 sandipgumtya wrote: Hi Mitch, The method I followed took me nearly 4 min.Can u pl suggest a quicker method or make it easier to understand? Sandip. An alternate approach is to PLUG IN THE ANSWERS, which represent the number of blueberries in each blue box. Answer choice D: 50 blueberries per box If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25. In other words, subtracting one box of 50 blueberries and adding in one box of S strawberries is equal to an increase of 25: -50 + S = 25 S = 75 strawberries per box. If Danny disposed of one blue box for one additional red box, the difference between the total number of strawberries and the total number of blueberries would increase by 95. Let Danny start with 2 boxes of strawberries and 2 boxes of blueberries. Original difference = (total strawberries) - (total blueberries) = (75+75) - (50+50) = 50. After one box of blueberries is exchanged for one box of strawberries, new difference = (75+75+75) - 50 = 175. (new difference) - (original difference) = 175-50 = 125. The increase in the difference is too great. Eliminate D. Answer choice B: 40 blueberries per box If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25. In other words, subtracting one box of 40 blueberries and adding in one box of S strawberries is equal to an increase of 25: -40 + S = 25 S = 65 strawberries per box. If Danny disposed of one blue box for one additional red box, the difference between the total number of strawberries and the total number of blueberries would increase by 95. Let Danny start with 2 boxes of strawberries and 2 boxes of blueberries. Original difference = (total strawberries) - (total blueberries) = (65+65) - (40+40) = 50. After one box of blueberries is exchanged for one box of strawberries, new difference = (65+65+65) - 40 = 155. (new difference) - (original difference) = 155-50 = 105. The increase in the difference is still too great. Eliminate B. Notice the pattern: In D, (new difference) - (original difference) = 125. In B, (new difference) - (original difference) = 105. The smaller the answer choice, the smaller the value of (new difference) - (original difference). Implication: To yield (new difference) - (original difference) = 95, the correct answer must be SMALLER than answer choice B. The correct answer is A. Answer choice A: 35 blueberries per box If Danny disposed of one blue box for one additional red box, the total number of berries (of both kinds) would increase by 25. In other words, subtracting one box of 35 blueberries and adding in one box of S strawberries is equal to an increase of 25: -35 + S = 25 S = 60 strawberries per box. If Danny disposed of one blue box for one additional red box, the difference between the total number of strawberries and the total number of blueberries would increase by 95. Let Danny start with 2 boxes of strawberries and 2 boxes of blueberries. Original difference = (total strawberries) - (total blueberries) = (60+60) - (35+35) = 50. After one box of blueberries is exchanged for one box of strawberries, new difference = (60+60+60) - 35 = 145. (new difference) - (original difference) = 145-50 = 95. Success! _________________ Mitch Hunt Private Tutor for the GMAT and GRE GMATGuruNY@gmail.com If you find one of my posts helpful, please take a moment to click on the "UPVOTE" icon. Available for tutoring in NYC and long-distance. For more information, please email me at GMATGuruNY@gmail.com. Student Review #1 Student Review #2 Student Review #3 Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now. GMAT/MBA Expert GMAT Instructor Joined 12 Sep 2012 Posted: 2635 messages Followed by: 116 members Upvotes: 625 Target GMAT Score: V51 GMAT Score: 780 We could also work with a couple equations. Suppose we have x red boxes, each of which has s strawberries, and y blue boxes, each of which has b blueberries. Before the change, we have (x + y) boxes and xs + by berries. After the change, we have (x + y) boxes and (x+1)s + (y - 1)b, or xs + by + s - b berries. We're told that Strawberries in a box - Blueberries in a box = 25, or s - b = 25 and (New Strawberries - New Blueberries) - (Old Strawberries - Old Blueberries) = 95, or ((x + 1)*s - (y - 1)*b) - (xs - yb) = 95 The second equation simplifies to s + b = 95 so we're set! s - b = 25 s + b = 95 Adding these together, we have 2s = 120, from which we find s = 60 and b = 35. Neat Q, surprisingly tricky to set up. Enroll in a Veritas Prep GMAT class completely for FREE. Wondering if a GMAT course is right for you? Attend the first class session of an actual GMAT course, either in-person or live online, and see for yourself why so many students choose to work with Veritas Prep. Find a class now! • 1 Hour Free BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • Award-winning private GMAT tutoring Register now and save up to$200

Available with Beat the GMAT members only code

• Get 300+ Practice Questions

Available with Beat the GMAT members only code

• FREE GMAT Exam
Know how you'd score today for \$0

Available with Beat the GMAT members only code

• 5 Day FREE Trial
Study Smarter, Not Harder

Available with Beat the GMAT members only code

• Free Trial & Practice Exam
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• 5-Day Free Trial
5-day free, full-access trial TTP Quant

Available with Beat the GMAT members only code

• Free Practice Test & Review
How would you score if you took the GMAT

Available with Beat the GMAT members only code

• Magoosh
Study with Magoosh GMAT prep

Available with Beat the GMAT members only code

Top First Responders*

1 Ian Stewart 53 first replies
2 Brent@GMATPrepNow 36 first replies
3 Jay@ManhattanReview 29 first replies
4 GMATGuruNY 25 first replies
5 ceilidh.erickson 15 first replies
* Only counts replies to topics started in last 30 days
See More Top Beat The GMAT Members

Most Active Experts

1 Scott@TargetTestPrep

Target Test Prep

199 posts
2 Max@Math Revolution

Math Revolution

90 posts
3 Brent@GMATPrepNow

GMAT Prep Now Teacher

76 posts
4 Ian Stewart

GMATiX Teacher

62 posts
5 GMATGuruNY

The Princeton Review Teacher

44 posts
See More Top Beat The GMAT Experts