Help with this one

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Help with this one

by aninditasivaram2406 » Sun Nov 11, 2007 2:28 pm
1. If x and y are integers and x>0, is y>0?
·7x-2y>0
·-y>x
Answer E

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Re: Help with this one

by jayhawk2001 » Sun Nov 11, 2007 9:48 pm
aninditasivaram2406 wrote:1. If x and y are integers and x>0, is y>0?
·7x-2y>0
·-y>x
Answer E
I would say B is sufficient. -y>x implies y < -x. Given that x is positive,
y has to be negative. I hope I'm not missing something obvious

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I agree

by aninditasivaram2406 » Mon Nov 12, 2007 7:24 am
Hi Jayhawk,

Thats what I had thought. But the answer appears to be E. This is from GMAT prep...any thoughts?

Thanks,
Anindita

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by enlightenment » Mon Nov 12, 2007 6:57 pm
The question only states that x and y are integers. Therefore, substitute positive AND negative values and zero for x.

In statement 2: "-y>x" can also be written as "y<x>0" Simplify to get "y<-7x/2." Again try plugging positive and negative values for x. We get the same result as statement 2. Insufficient.

Combining Statements 1 and 2 they pretty much say the same thing as they do individually, only that statement 1 has a multiplier of 7/2. Statements 1 and 2 taken together are not sufficient. (E)


I always forget to check for +, -, and 0 on DS questions myself.

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by ri2007 » Tue Nov 13, 2007 5:00 am
enlightenment wrote:The question only states that x and y are integers. Therefore, substitute positive AND negative values and zero for x.

In statement 2: "-y>x" can also be written as "y<x>0" Simplify to get "y<-7x/2." Again try plugging positive and negative values for x. We get the same result as statement 2. Insufficient.

Combining Statements 1 and 2 they pretty much say the same thing as they do individually, only that statement 1 has a multiplier of 7/2. Statements 1 and 2 taken together are not sufficient. (E)


I always forget to check for +, -, and 0 on DS questions myself.
enlightenment, the question also says that both X & Y are greater than 0. So we cannot assume a -ve value for eithe x or y

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by enlightenment » Tue Nov 13, 2007 8:25 am
ri2007 wrote:
enlightenment wrote:The question only states that x and y are integers. Therefore, substitute positive AND negative values and zero for x.

In statement 2: "-y>x" can also be written as "y<x>0" Simplify to get "y<-7x/2." Again try plugging positive and negative values for x. We get the same result as statement 2. Insufficient.

Combining Statements 1 and 2 they pretty much say the same thing as they do individually, only that statement 1 has a multiplier of 7/2. Statements 1 and 2 taken together are not sufficient. (E)


I always forget to check for +, -, and 0 on DS questions myself.
enlightenment, the question also says that both X & Y are greater than 0. So we cannot assume a -ve value for eithe x or y
wow...perfect example of why you should read the question stem completely.

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Confused :(

by aninditasivaram2406 » Tue Nov 13, 2007 8:45 am
now i am confused! please can someone tell me what is the correct answer to this one? Thanks!

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by enlightenment » Tue Nov 13, 2007 11:21 am
Anonymous wrote:
enlightenment wrote:The question only states that x and y are integers. Therefore, substitute positive AND negative values and zero for x.
This is where the gap in logic is hitting me. The question states that x > 0. So why are you subbing in 0 and negatives when they don't exist for x?
Read above. I did not read the question stem correctly.

on a side note. i need to remember to turn the html in the post off. When you use < or > the forum thinks you are writing htmp tags and changes your text a little. And i really am not following what i wrote last night, either. I must have been pretty tired because i am some how mixing the two statements together. Sorry for the confusion.

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by gabriel » Tue Nov 13, 2007 12:29 pm
Now, that the enlightened one :) has cleared the air about his post .. can we agree on an answer ?? .. what does thou say oh enlightened one :) .. B or E ..

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by enlightenment » Tue Nov 13, 2007 12:34 pm
gabriel wrote:Now, that the enlightened one :) has cleared the air about his post .. can we agree on an answer ?? .. what does thou say oh enlightened one :) .. B or E ..
B

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by gabriel » Tue Nov 13, 2007 12:36 pm
B for me too ..