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## Help on some doubts

This topic has 3 member replies
Caps Junior | Next Rank: 30 Posts
Joined
11 Feb 2007
Posted:
19 messages

#### Help on some doubts

Sun Jun 10, 2007 8:47 am
Hi guys
Can you help me on some doubts I have on Maths? Please see attach document

regards
Caps
Attachments

givemeanid Master | Next Rank: 500 Posts
Joined
17 Jun 2007
Posted:
277 messages
Followed by:
1 members
6
Thu Aug 02, 2007 8:55 am
Caps, please post one question per post. This helps to keep everything organized and focused on one topic.

Also, make sure you post each question in the appropriate section of the forum.

_________________
So It Goes

priyasom Newbie | Next Rank: 10 Posts
Joined
29 May 2007
Posted:
2 messages
Thu Aug 02, 2007 12:59 am
3. A sphere with diameter 6 is inscribed into a squared box. What is the greatest stick that we can put between the sphere and the box?

I have attached a 2D view of a sphere in a square box. We can assume that the edges of the square act as tangents to the circle. Then maximum length of a stick that can be inserted between the sphere and the box will be equal to the radius of the circle = 3.

Corner right triangle that will be formed will have sides of length 3 each. But we cannot insert a stick of length equal to that of a hypotenuse because it will be blocked by the sphere. Hence maximum length possible is that of the edge of the triangle = radius of the circle = 3.
Attachments

vrider Junior | Next Rank: 30 Posts
Joined
01 May 2007
Posted:
17 messages
Sun Jun 10, 2007 3:47 pm
1. 1/x^2+6/x+9 =0

multiply all terms by x^2
1+6x+9x^2 = 0

factorizing, 9x^2 = 3x*3x
9x^2 + 3x + 3x + 1 = 0

(3x+1)^2 = 0

x = -1/3

2. x^2(x^4+2*x^2-35) = 0

x^2 = 0 gives x =0 as one root.

solving for the other polynomial, you'll see
-35*x^4 = 7*x^2 * -5*x^2

so, (x^2-5)(x^2+7) =0

x^2 =5 gives x = +/- rt. 5

so , 3 real factors.

I wish I could post it better but typing out exponents & mathematical expressions in text are just painful, so I am trying to shorten it here.

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