BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Help Me out with this Combinotrics prob. from GMATPREP

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 15
Joined: Sat Aug 08, 2009 7:07 am
Location: PUNJAB
GMAT Score:610
by DREAM GMAT » Sat Oct 10, 2009 9:07 pm
Each stack is designated with a 1, 2, and 3 letter code where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitutes a different code, how many different stocks is it possible to uniquely designate with these codes?
a. 2951
b. 8125
c. 15600
d. 16302
e. 18278

I Guessed the answer which was correct, but need the explanation for the same.

Thanks
MANDEEP
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 399
Joined: Wed Apr 15, 2009 3:48 am
Location: india
Thanked: 39 times

by xcusemeplz2009 » Sun Oct 11, 2009 2:34 am
IMO E

26+26*26+26*26*26
It does not matter how many times you get knocked down , but how many times you get up
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Tue Sep 22, 2009 8:25 pm

by rdchandvadkar » Fri Feb 12, 2010 1:15 pm
could some one explain this one in a lil detail..

this is what i did.

for 1 alphabet code- 26 ways.
for 2 alphabet code- 26P2= 26*25
for 3 alphabet code- 26P3= 26*25*24

and then add them together....

whats is wrong... im missing something here.. pls explain from the start.. permutation and combination is a major bother for me.

thanks..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Tue Sep 22, 2009 8:25 pm

by rdchandvadkar » Fri Feb 12, 2010 1:26 pm
i think i got the logic...

for 1 alphacode: 26 ways..
for 2 alphacode: the 1st alpha can be selected from 26 available; the 2nd alpha can be selected from 26 available alpha(as the same alpha can be used)
similarly for 3 alphacode.

therefore 26+26^2+26^3


hope this is the right logic i have used this time around.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1560
Joined: Tue Nov 17, 2009 2:38 amFollowed by: 5 members
Thanked: 137 times

by thephoenix » Fri Feb 12, 2010 7:23 pm
rdchandvadkar wrote:i think i got the logic...

for 1 alphacode: 26 ways..
for 2 alphacode: the 1st alpha can be selected from 26 available; the 2nd alpha can be selected from 26 available alpha(as the same alpha can be used)
similarly for 3 alphacode.

therefore 26+26^2+26^3


hope this is the right logic i have used this time around.
yes this the right approach for this one since the question says repetetion is allowed for each pace we hace 26 choices

had there been no repetetion.....the ans wud have been

26c1+26c2+26C3=2951
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1