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this question has been discussed quite a few times but I DON'T GET IT. Can someone please help this dumb person understand this:
I looked at following explanation but I dont understand why we need value for ab and why we are worried about (a+b). some background will be helpful..
In the XY-Plane, at what two points does the graph of y=(x+a)(x+b) intersect the x-axis
1) a+b= -1
2) The graph intersects the y-axis at (0,-6)
at x axis: y=0 ; x^2+(a+b)x+ab=0
1) a+b= -1 -insuffi
2) The graph intersects the y-axis at (0,-6); ==> ab=-6 -- insuff
both: suffi.
it is C...!!
From 1, a+b=-1.
From 2, x=0, so ab=6.
(x+a)*(x+b)=0
x^2+(a+b)x+ab=0
So, x=-3, x=2
The answer is C.
y = x^2 + (a+b)x + ab
A) a+b = -1..
But dont know ab
B) When x = 0, y = -6
Put in the 1st equation
We get, ab = -6
But dont know (a+b)
Combining C) y = x^2 -x -6
When it intersects x axis, y =0...
Thus, x^2-x-6 = 0.
The parabola cuts the x-axis at 3 and -2.
Hence, C