gprep triangles
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Ok. You have 2 similar triangles in this problem.
s is the base of small triangle, S is that of a big one.
So sides and height of a big triangle may be expressed as k*s=S and k*h=H, where s is a base, and h - is a height.
(NB: k is a coefficient, literally - a ratio of S and s)
the area of small triangle equals :
1/2*h*s
whereas the area of big one equals:
1/2*kh*ks
we know that the area of a big triangle is twice the area of a small one.
2(1/2*h*s)=1/2kh*ks
h*s=1/2kh*ks
1=1/2k^2 ==> k^2=2 and k=sqrt(2).
Hence S=s*k=sqrt(2)s.
hope it helpes.
s is the base of small triangle, S is that of a big one.
So sides and height of a big triangle may be expressed as k*s=S and k*h=H, where s is a base, and h - is a height.
(NB: k is a coefficient, literally - a ratio of S and s)
the area of small triangle equals :
1/2*h*s
whereas the area of big one equals:
1/2*kh*ks
we know that the area of a big triangle is twice the area of a small one.
2(1/2*h*s)=1/2kh*ks
h*s=1/2kh*ks
1=1/2k^2 ==> k^2=2 and k=sqrt(2).
Hence S=s*k=sqrt(2)s.
hope it helpes.
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its a direct formula q
for two similar tri
a1/a2=(s1)^2/(s2)^2
a2=2a1
i.e
1/2=s^2/S^2
or S=s*rut2
for two similar tri
a1/a2=(s1)^2/(s2)^2
a2=2a1
i.e
1/2=s^2/S^2
or S=s*rut2
It does not matter how many times you get knocked down , but how many times you get up
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- Master | Next Rank: 500 Posts
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