Please find attached a snapshop of the problem.
Thank you in advance!
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Goemetry - Circles 2!
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varun7nurav
- Senior | Next Rank: 100 Posts
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Dear guys, this is another problem. I am able to determine the answer but the method is pretty lengthy. Please do suggest any shorter way to get the solution.
Please find attached a snapshop of the problem.
Thank you in advance!
Please find attached a snapshop of the problem.
Thank you in advance!
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GMATGuruNY
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I posted a solution to a very similar problem here:
https://www.beatthegmat.com/triangle-ins ... 90961.html
https://www.beatthegmat.com/triangle-ins ... 90961.html
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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The way I would have done it is create an isosceles triangle within the equilateral triangle using the radius (the sides of this new triangle will go from the center of the circle to two different points of the equilateral triangle). Then I would have used the isosceles relationship 1:1:2^(1/2) to determine that the length of one side of the equilateral triangle is 4*2^(1/2). Multiply that by 3 (since we're looking for the perimeter) and you get the answer 12*2^(1/2), or C.
What's the OA?
What's the OA?
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varun7nurav
- Senior | Next Rank: 100 Posts
- Posts: 33
- Joined: Fri Nov 19, 2010 8:07 am
cbaum,
your approach of using the radius to get the side is right.Although, you do not get a 1-1-2^1/2 here as its NOT a 45-45-90 triangle. Instead if u split that isos triangle into 2 triangles by dropping a perpendicular, u get a 30-60-90 i.e. 1-3^(1/2)-3 triangle. From this we get that (side of the equilateral triangle/2) = 4root3. Answer is therefore 12root3.
Cheers!
your approach of using the radius to get the side is right.Although, you do not get a 1-1-2^1/2 here as its NOT a 45-45-90 triangle. Instead if u split that isos triangle into 2 triangles by dropping a perpendicular, u get a 30-60-90 i.e. 1-3^(1/2)-3 triangle. From this we get that (side of the equilateral triangle/2) = 4root3. Answer is therefore 12root3.
Cheers!
Thanks! Realized shortly after I posted that with my way the circle would only equal 270 degreesvarun7nurav wrote:cbaum,
your approach of using the radius to get the side is right.Although, you do not get a 1-1-2^1/2 here as its NOT a 45-45-90 triangle. Instead if u split that isos triangle into 2 triangles by dropping a perpendicular, u get a 30-60-90 i.e. 1-3^(1/2)-3 triangle. From this we get that (side of the equilateral triangle/2) = 4root3. Answer is therefore 12root3.
Cheers!
