BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMATPrep Q

Expert replies
Source: — Problem Solving |

Re: GMATPrep Q

by California4jx » Tue Aug 26, 2008 2:39 pm
smehmood wrote:How do we solve the attached Q?
thanks
M
Sum of four numbers is: 30 * 4 = 120

Start from (II): 120 - (9+10) = 101 { You cant get anything more out of this statement, so itself it is INSUF }

(I): the max number is 60 (INSUFF)

Combine two: 101 - 60 = 41, therefore 2 numbers are more than 30.

C is the answer
Join the discussion

by smehmood » Tue Aug 26, 2008 3:40 pm
But I doesn't say that max number is 60?
Join the discussion

by somail » Tue Aug 26, 2008 4:25 pm
Yes it does.

Look at it this way. After statement 2, you have 101 remaining. using the two remaining number combinations, how can you get 101:

100 + 1
60 + 41
30 + 71

But.. Statement 1 states the max number is 60, we use 60 as the max number to see how small the fouth number could possibly be. Since the fourth number is 101-60=41, we know that the 3rd and 4th number must be above 30.
Join the discussion

by nervesofsteel » Tue Aug 26, 2008 5:04 pm
yes C is the answer

using A there can be two options 0,1,59,60 so 2 numbers are more than 30
or 0,31,44,45 now 3 are more than 30... So A is insufficient

Using B 9,10, 1, 100 - 1 is more than 30
or 9,10,31,70 - 2 are more than 30 -- Insufficient

Now using both together...

9,10,41,60 -- 2 more than 30


So keeping 9 and 10 as fixed and no number greater than 60 .. there will be always
2 numbers greater than 30.... C is sufficient
Join the discussion

by john555 » Tue Aug 26, 2008 7:51 pm
Answer is C.

Statement 1 is insufficient to answer

statement 2 shows two numbers whose sum is 19. It is also insuff.

Combining 1 & 2 : One can answer .

The sum of other two numbers is 111. One number is varies from 60, 59,58....to 55. Other number is varies from 55 to 60.
Join the discussion