Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

GMATPrep Geometry Bugger

Expert replies
by stellategang » Mon Feb 04, 2008 10:33 am
Nothing indicates in the question that ACO is a triangle. If ABCO could be a quadrilateral then this question is impossible to answer. Does anyone feel me on this?

I put E because I thought ABCO could be a quadrilateral . . . the OA is D, which I assume presumes that ACO is a triangle although nothing is stated.

Thanks for the help
You do not have the required permissions to view the files attached to this post.
Join the discussion
Source: — Data Sufficiency |

tip

by tutonaranjo » Mon Feb 04, 2008 5:23 pm
unless it specifically says "figure not drawn to scale" you can use the diagram for reference
Join the discussion

OA explanation?

by meghamehta15 » Mon Feb 04, 2008 6:37 pm
Hey can you tell me how you arrived on the answer D?

What is the explanation to the OA?
Join the discussion

Re: tip

by Stuart@KaplanGMAT » Mon Feb 04, 2008 6:52 pm
tutonaranjo wrote:unless it specifically says "figure not drawn to scale" you can use the diagram for reference
Problem solving diagrams ARE drawn to scale unless they specifically state otherwise.

On the other hand, data sufficiency diagrams are NOT necessarily drawn to scale. It is NOT safe to rely on the way things look, we can only rely on explicitly stated information.

However, there are a few exceptions to this general rule, one of which is that if a line looks like it's straight, we can rely on it being straight.

Here's the scoop taken directly from the test directions (emphasis mine):
Figures

A figure accompanying a data sufficiency question will conform to the information given in the question but will not necessarily conform to the additional information given in statements (1) and (2).

Lines shown as straight can be assumed to be straight and lines that appear jagged can also be assumed to be straight.

You may assume that the positions of points, angles, regions, etc. exist in the order shown and that angle measures are greater than zero.

All figures lie in a plane unless otherwise indicated.
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

solution

by tutonaranjo » Tue Feb 05, 2008 2:54 pm
Name angles like this>
angle BAO = x
angle BOA = x (triangle is isoceles because BO is a radius and it is = CO = AB)
angle OBC = y
angle BCO = y (triangle is isoceles, two sides are radii)
angle BOC = 180 - 2y

Solve this.
angle CAO+ACO+AOC = 180 ... translated this means
x + y + x + 180-2y = 180 solves to>
2x=y
so actually, angles OBC and BCO are 2x

Now...
name angle BDC = z (this was previously named 180-2y)

statement 1 says angle COD = 60
60+z+x = 180 (the are all supplementary right?) another equation>
4x+z = 180 (from triangle BOC angles add 180)

x+z = 120 (equation 1)
-4x-z = -180 (equation 2 multiplied by -1)
-3x=-60
x=20
SUFFICIENT

Statement 2 gives you the value of 2x, so you can figure X

:)
Join the discussion

by stellategang » Tue Feb 05, 2008 6:12 pm
tutonaranjo and Stuart,

Thanks for the insight, will be using that approach from now on :)
Join the discussion