Attached is a question from GMAT Prep Test 2. Please advise how to achieve the result. Answer: B Thanks, K

kwah wrote:Attached is a question from GMAT Prep Test 2. Please advise how to achieve the result. Answer: B Thanks, K Area of square garden = A sq ft Perimeter of square garden = P ft A = 2P + 9 Let us assume that each side of the square garden = s² sq ft Then A = s² and P = 4s So, A = 2P + 9 implies s² = 2 *(4s) + 9 s² = 8s + 9 s² - 8s - 9 = 0 s² - 9s + s - 9 = 0 s(s - 9) + 1(s - 9) = 0 (s + 1)(s - 9) = 0 s = 9, (s = -1 is not possible, as side cannot be negative) Therefore, perimeter of square garden = 4 * 9 = 36 ft The correct answer is B.

Let us assume the side of the square to be 'a' cm. So, its area A = a^2 sq.cm Perimeter P = 4a. Given A = 2P + 9 We will now plug in the values of A and P in the above equation. We get, a^2 = 2(4a) + 9 a^2 = 8a + 9 ==> a^2 - 8a - 9 = 0 ==> a^2 - 9a + a - 9 = 0 [factors 0f 9 such that difference is 8 and product is 9 is -9 and 1] ==> a(a - 9) + 1(a - 9) = 0 ==> (a - 9)(a + 1) = 0 ==> a = 9 or -1. We will consider 'a' = 9 as the measurement of length cannot be < 0. Hence, the perimeter P = 4a = 4(9) = 36cm.

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