BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep2 ? (Team)

Expert replies
Source: — Problem Solving |

by aatech » Wed May 14, 2008 10:28 am
I am a lil confused on this one.. There are 3 teams with 3 members each so there are total 9
members. But max value of n is only 5.. so, I guess anyone finishing 5th to 9th will get 1 point
each..

In that case least point acquired by a team would be when all 3 members of the team finish
between position 5th to 9th...

So total point would be 1+1+1 = 3..

This would be my take on it.... anyone else???
Join the discussion

by tacobell » Wed May 14, 2008 6:31 pm
The way I see it is that there are 9 racers and that only the top 5 finishers are given points since 6-n points are given when 1<=n<=5.
Since no team will earn more than 6 points, One team could receive 5 (1st place) and 1 (5th place), and second team could receive 4 (2nd place) and 2 (4th place). Therefore the last time would receive 3 points. There's probably a mathematically expression to this problem but this is the logic I followed.
Join the discussion

by Magellan » Thu May 15, 2008 2:14 am
Total points to be distributed:
6 - 5 = 1
6 - 4 = 2
6 - 3 = 3
6 - 2 = 4
6 - 1 = 5
Total: 1+2+3+4+5 = 15

Least possible score of team C when team A and B have the maximum possible score.

If A has 6pts and B has 6pts, there are still 3 points to be taken by the team C
Join the discussion