Gmat prep2 q3
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- simplyjat
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I am not sure why people prefer for upload a document, instead of just uploading the picture? Picture is great as it keeps the viewer in the same page and does not require 2-3 extra steps to just see the question...
I just ignore the questions that include another document?
Is it really that hard to upload the picture ?
I just ignore the questions that include another document?
Is it really that hard to upload the picture ?
simplyjat
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because some people have difficulties to upload from my computer. That's why. Come on, it will take you one more step to open the file (not too hard I guess)... I saw your post on your score. Keep fighting!!
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The only way we can get x^2 - y^2 as the product of those terms is if we have a difference of squares. Any other binomial product will also have an "xy" term in the middle.
The only way we can get a difference of squares from the terms shown is (x-y)(x+y).
So, we're choosing 2 of the 4 terms. 4C2 = 4!/2!2! = 4*3/2 = 6 total possible pairs.
Only 1 of the 6 possible pairs will give us what the question is asking for.
Prob = # desired outcomes / total # of possibilities = 1/6: choose (e)
The only way we can get a difference of squares from the terms shown is (x-y)(x+y).
So, we're choosing 2 of the 4 terms. 4C2 = 4!/2!2! = 4*3/2 = 6 total possible pairs.
Only 1 of the 6 possible pairs will give us what the question is asking for.
Prob = # desired outcomes / total # of possibilities = 1/6: choose (e)
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The only way we can get an answer without an xy term in the middle is if we start with a difference of squares.meghamehta15 wrote:how can we tell that only one will give the answer. I understand the first part about how you arrived at 6 ways but the second part is unclear..
For example, if we expand:
(x + y)(x + 5y)
we get:
x^2 +xy +5xy + y^2 = x^2 + 6xy + y^2
Since the question says the answer can be written in the form of:
x^2 - (by)^2,
we know that there can't be an xy term in our product. Since the only pair of terms that will give us a difference of squares is (x-y) and (x+y), only 1 out of the 6 possible pairings matches what we're looking for.
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