after solving both .
3Z < M < 4Z
now let say M = 3.5 Z,
now putting in main eq ie is M + Z > 0
ie M + 3.5 Z > 0
or 4.5 Z > 0
can't say because Z still can be negative.
So i found and E
but OA is different
plz help..
ta
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maihuna
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Aha so u donot got the expert only reply so reposting is't.
I think someone/may be u recently posted this Q.
C is a clear ans:
Adding both statements it gives : z>0
1 says : m>3z => m>0
COmbining m>0 as z>0
so m+z>0
It is a clear C, what is the confusion?
I think someone/may be u recently posted this Q.
C is a clear ans:
Adding both statements it gives : z>0
1 says : m>3z => m>0
COmbining m>0 as z>0
so m+z>0
It is a clear C, what is the confusion?
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Anurag@Gurome
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(1) m - 3z > 0 or m > 3z. From here we cannot say whether m + z > 0.
So, (1) is NOT SUFFICIENT.
(2) 4z - m > 0 or 4z > m. Again we cannot say whether m + z > 0.
So, (2) is NOT SUFFICIENT.
Combining (1) and (2), 3z < m < 4z
If z = -1, then the above inequality becomes -3 < m < -4, but that is not true as -3 > -4. Hence z can never be negative as 3z < m < 4z turns false in that case.
This implies z has to be positive and since m lies between 3z and 4z, which are positive so m will also be positive. Hence m + z > 0 is true.
The correct answer is C.
So, (1) is NOT SUFFICIENT.
(2) 4z - m > 0 or 4z > m. Again we cannot say whether m + z > 0.
So, (2) is NOT SUFFICIENT.
Combining (1) and (2), 3z < m < 4z
If z = -1, then the above inequality becomes -3 < m < -4, but that is not true as -3 > -4. Hence z can never be negative as 3z < m < 4z turns false in that case.
This implies z has to be positive and since m lies between 3z and 4z, which are positive so m will also be positive. Hence m + z > 0 is true.
The correct answer is C.
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maihuna
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Anurag,
you can simply add the two stmts that gives z>0
No need to cumbersome arithmetic, preety st forward.
you can simply add the two stmts that gives z>0
No need to cumbersome arithmetic, preety st forward.
Anurag@Gurome wrote:(1) m - 3z > 0 or m > 3z. From here we cannot say whether m + z > 0.
So, (1) is NOT SUFFICIENT.
(2) 4z - m > 0 or 4z > m. Again we cannot say whether m + z > 0.
So, (2) is NOT SUFFICIENT.
Combining (1) and (2), 3z < m < 4z
If z = -1, then the above inequality becomes -3 < m < -4, but that is not true as -3 > -4. Hence z can never be negative as 3z < m < 4z turns false in that case.
This implies z has to be positive and since m lies between 3z and 4z, which are positive so m will also be positive. Hence m + z > 0 is true.
The correct answer is C.
Charged up again to beat the beast
