GMAT PREP ?
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2/3 of 60 animals is either cow or pig. So total number of cow and pig is (2/3 * 60) = 40.
Stmt-1. c > 2p -> so c + p = 40 => (In worst case-when c = 2p->) 3p = 40 => p = 13. ...
Now if p = 13, c = 27 so that c + p =40
Stmt-2, p > 12 -> if p = 13, c = 27 so c + p =40 but if p = 14, c = 28 (in worst case when c = 2p) c + p = 42.
So we can come to know the fact there are 27 cows in total.
I will go for D. Whats the OA?
Stmt-1. c > 2p -> so c + p = 40 => (In worst case-when c = 2p->) 3p = 40 => p = 13. ...
Now if p = 13, c = 27 so that c + p =40
Stmt-2, p > 12 -> if p = 13, c = 27 so c + p =40 but if p = 14, c = 28 (in worst case when c = 2p) c + p = 42.
So we can come to know the fact there are 27 cows in total.
I will go for D. Whats the OA?
Correct me If I am wrong
Regards,
Amitava
Regards,
Amitava
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The answer should be C
From the question we know that 40 are either Cows or Pigs
(1) Says that there are "More" than twice as many cows as pigs. Lets plug values and find out
if P=2 then C=38(more than twice as many pigs)
if p=6 then C=34(more than twice as many pigs)
So A is insufficient
(2) says that P>12. This information is insufficient as well.
When we combine both statements we know that P>12 and so
if p=13 then C=27(which is more than twice of P)
There is no ther combination which will satisfy the combined condition.
Hence the answer is C
From the question we know that 40 are either Cows or Pigs
(1) Says that there are "More" than twice as many cows as pigs. Lets plug values and find out
if P=2 then C=38(more than twice as many pigs)
if p=6 then C=34(more than twice as many pigs)
So A is insufficient
(2) says that P>12. This information is insufficient as well.
When we combine both statements we know that P>12 and so
if p=13 then C=27(which is more than twice of P)
There is no ther combination which will satisfy the combined condition.
Hence the answer is C
Maxx
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But Moneyman, u r losing a point that is mentioned in the Qs - i.e. no of cow + no of pig = 40. Now if u plug stmt-1, it will work. Got my point? Let me know if I am wrong!moneyman wrote:The answer should be C
From the question we know that 40 are either Cows or Pigs
(1) Says that there are "More" than twice as many cows as pigs. Lets plug values and find out
if P=2 then C=38(more than twice as many pigs)
if p=6 then C=34(more than twice as many pigs)
So A is insufficient
(2) says that P>12. This information is insufficient as well.
When we combine both statements we know that P>12 and so
if p=13 then C=27(which is more than twice of P)
There is no ther combination which will satisfy the combined condition.
Hence the answer is C
Correct me If I am wrong
Regards,
Amitava
Regards,
Amitava
I agree. I think that in the question we learn that either all cows together are 40 or all pigs together are 40.
If statment 1 is true, then the pigs cannot be 40 (as all animals on the farm ar 60). Cows then need to be 40 and pigs less than 20.
If statement 2 is true, we still don't know the answer, because more than 12 pigs could be 40 or not. This leaves us with no answer for how many cows are there.
I would go for A.
???
If statment 1 is true, then the pigs cannot be 40 (as all animals on the farm ar 60). Cows then need to be 40 and pigs less than 20.
If statement 2 is true, we still don't know the answer, because more than 12 pigs could be 40 or not. This leaves us with no answer for how many cows are there.
I would go for A.
???
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Hi Amitava,
I dont think A is sufficient because the question asks for the exact number of cows among the total 40 and A would give different choices cows as well as for pigs. Just plug in numbers and you will see.
I dont think A is sufficient because the question asks for the exact number of cows among the total 40 and A would give different choices cows as well as for pigs. Just plug in numbers and you will see.
Maxx