The y-intercept of a line l is 4. If the slope of l is negative, which of the following could be the x-intercept of l?
I. -1
II. 0
III. 6
a. I only
b. II only
c. III only
d. I, II, and III
e. I and II only
OA: b
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- Anurag@Gurome
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Say the equation of l is y = mx + ctrangle wrote:The y-intercept of a line l is 4. If the slope of l is negative, which of the following could be the x-intercept of l?
I. -1
II. 0
III. 6
a. I only
b. II only
c. III only
d. I, II, and III
e. I and II only
Where m is the slope and c is the y-intercept.
Now, x-intercept of the line is the value of x, when y is zero.
=> x-intercept = -(c/m)
According to the question, c = 4 and m < 0.
Hence, x-intercept = -(c/m) = -(4/m) = Some positive quantity as m < 0.
Possible value of x-intercept is 6.
The correct answer is C.
Note: Check the OA again. If x-intercept of the line is zero, then the line can never have a negative slope. Then it'll be perpendicular to x-axis, i.e. of infinite slope.
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- pesfunk
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Even my answer comes to C. It must be the right answer.
Anurag@Gurome wrote:Say the equation of l is y = mx + ctrangle wrote:The y-intercept of a line l is 4. If the slope of l is negative, which of the following could be the x-intercept of l?
I. -1
II. 0
III. 6
a. I only
b. II only
c. III only
d. I, II, and III
e. I and II only
Where m is the slope and c is the y-intercept.
Now, x-intercept of the line is the value of x, when y is zero.
=> x-intercept = -(c/m)
According to the question, c = 4 and m < 0.
Hence, x-intercept = -(c/m) = -(4/m) = Some positive quantity as m < 0.
Possible value of x-intercept is 6.
The correct answer is C.
Note: Check the OA again. If x-intercept of the line is zero, then the line can never have a negative slope. Then it'll be perpendicular to x-axis, i.e. of infinite slope.