BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

GMAT Prep

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 30
Joined: Thu Feb 22, 2007 5:56 pm
Location: Seattle

GMAT Prep

by josephcho77 » Sun Sep 23, 2007 12:07 am
What is the greatest possible area of a triangular region with one vertex at the center of a circle of radius 1 and the other two vertices on the circle?

A. squ. root 3/4
B. 1/2
C. pi/4
D. 1
E. squ. root 2



Can you help to solve this problem?
Thanks!
Top
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 21
Joined: Sun Aug 26, 2007 11:45 am

by cindyqtran » Sun Sep 23, 2007 9:09 am
is the answer B?

since we know that one of the side is 1, so the largest length of the other side is 1. so A = 0.5bh = .5*1*1 = .5
Top
Senior | Next Rank: 100 Posts
Posts: 30
Joined: Thu Feb 22, 2007 5:56 pm
Location: Seattle

by josephcho77 » Sun Sep 23, 2007 7:00 pm
Yes, the answer is B.

Thanks
Top
Post new topic Post Reply
• Page 1 of 1