If c and d are integers is c even ?
1) c(d+1) is even
2) (c+2)(d+4) is even
Looking for any short cut or easy method of solving this question. At the moment i solved it putting in numbers for diff even/odd combination .
OA C
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Statement 1: c(d + 1) is even implies any one of the following three possible scenarioschaitanya.mehrotra wrote:If c and d are integers is c even ?
1) c(d+1) is even
2) (c+2)(d+4) is even
- 1. c is even, (d + 1) is odd --> c and d both even
2. c is odd, (d + 1) is even --> c and d both odd
3. c and (d + 1) both even --> c even, d odd
Statement 2: (c + 2)(d + 4) is even implies any one of the following three possible scenarios
- 1. (c + 2) is even, (d + 4) is odd --> c even, d odd
2. (c + 2) is odd, (d + 4) is even --> c is odd, d even
3. both (c + 2) and (d + 4) are even --> c and d both even
1 & 2 Together: Only feasible scenarios are (c even, d odd) or (c and d both even). Hence, c is always even.
Sufficient
The correct answer is C.
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