Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

GMAT Prep question - really tough one - LCM, GCF factor etc.

Expert replies
by psriniva » Tue Jun 17, 2008 12:07 pm
The integers m and p such that 2 < m <p> 1.

1. The greatest common factor of m and p is 2.
2. The least common multiple of m and p is 30.

The correct answer is A

Your help is appreciated.

Paddy
Paddy Srinivas
Join the discussion
Source: — Data Sufficiency |

by VP_Tatiana » Wed Jun 18, 2008 5:44 am
Hi there,

I'm taking to mean 2<m<p>1 to mean 2<m<p>1. However, this seems a little redundant as if 2<p then of course 1<p.

1 is insufficient on its own because more than one value of m and p satisfy the condition. For instance, we could have p=6, m =4, or p=10 and m=8.


2 is insufficient on its own again because more than one value of m and p satisfy the condition. For instance, we could have p=6, m =5, or p = 10 and m=3.

However, I can only find one value of m and p that satisfies both conditions: p =30, m =2. Thus, 1+2 together are sufficient and the answer is C. I don't know why your guide says the answer is A; the only thing I can think of is that maybe you meant something else by 2<m<p>1. Let me know.

Best wishes,

Tatiana
Tatiana Becker | GMAT Instructor | Veritas Prep
Join the discussion

by egybs » Wed Jun 18, 2008 1:33 pm
What's the question!?
Join the discussion

by rakesheval » Sat Jun 21, 2008 8:32 am
i think the answer should be E instead of A or C...two sets (30,2) and (6,10) satisfy both the conditions given in the two statements..
Join the discussion