The integers m and p such that 2 < m <p> 1.
1. The greatest common factor of m and p is 2.
2. The least common multiple of m and p is 30.
The correct answer is A
Your help is appreciated.
Paddy
GMAT Prep question - really tough one - LCM, GCF factor etc.
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Hi there,
I'm taking to mean 2<m<p>1 to mean 2<m<p>1. However, this seems a little redundant as if 2<p then of course 1<p.
1 is insufficient on its own because more than one value of m and p satisfy the condition. For instance, we could have p=6, m =4, or p=10 and m=8.
2 is insufficient on its own again because more than one value of m and p satisfy the condition. For instance, we could have p=6, m =5, or p = 10 and m=3.
However, I can only find one value of m and p that satisfies both conditions: p =30, m =2. Thus, 1+2 together are sufficient and the answer is C. I don't know why your guide says the answer is A; the only thing I can think of is that maybe you meant something else by 2<m<p>1. Let me know.
Best wishes,
Tatiana
I'm taking to mean 2<m<p>1 to mean 2<m<p>1. However, this seems a little redundant as if 2<p then of course 1<p.
1 is insufficient on its own because more than one value of m and p satisfy the condition. For instance, we could have p=6, m =4, or p=10 and m=8.
2 is insufficient on its own again because more than one value of m and p satisfy the condition. For instance, we could have p=6, m =5, or p = 10 and m=3.
However, I can only find one value of m and p that satisfies both conditions: p =30, m =2. Thus, 1+2 together are sufficient and the answer is C. I don't know why your guide says the answer is A; the only thing I can think of is that maybe you meant something else by 2<m<p>1. Let me know.
Best wishes,
Tatiana
Tatiana Becker | GMAT Instructor | Veritas Prep
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i think the answer should be E instead of A or C...two sets (30,2) and (6,10) satisfy both the conditions given in the two statements..