2^5 + 2^5 + 3^5 + 3^5 + 3^5
a. 5^6
b. 13^5
c. 2^7 + 3^8
d. 4^5 + 9^5
e. 2^6 + 3^6
I know this question has to be solved by factoring, but not sure how to approach.
OA after a few explanations.
thanks
Andrew
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Answer is E.
2^5 + 2^5 + 3^5 + 3^5 + 3^5
= (2^5 + 2^5) + (3^5 + 3^5 + 3^5)
= 2^5(1 + 1) + 3^5(1 + 1 + 1)
= 2^5(2) + 3^5(3)
=2^6 + 3^6
Hope it helps.
2^5 + 2^5 + 3^5 + 3^5 + 3^5
= (2^5 + 2^5) + (3^5 + 3^5 + 3^5)
= 2^5(1 + 1) + 3^5(1 + 1 + 1)
= 2^5(2) + 3^5(3)
=2^6 + 3^6
Hope it helps.
mbadrew wrote:2^5 + 2^5 + 3^5 + 3^5 + 3^5
a. 5^6
b. 13^5
c. 2^7 + 3^8
d. 4^5 + 9^5
e. 2^6 + 3^6
I know this question has to be solved by factoring, but not sure how to approach.
OA after a few explanations.
thanks
Andrew
Attempt 1: 710, 92% (Q 42, 63%; V 44, 97%)
Attempt 2: Coming soon!
Attempt 2: Coming soon!