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gmat prep probability
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NOt really, but you can quicken things by cancelling: For example:
18!/(4!*14!)=
18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1
_____________________________________________
(4*3*2*1) * (14*13*12*1*/10*9*8*7*6*5*4*3*2*1)
Notice how you can cancell out a large portion of the top number, so you get:
18*17*16*15
___________
4*3*2*1
73,440/24=3,060
18!/(4!*14!)=
18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1
_____________________________________________
(4*3*2*1) * (14*13*12*1*/10*9*8*7*6*5*4*3*2*1)
Notice how you can cancell out a large portion of the top number, so you get:
18*17*16*15
___________
4*3*2*1
73,440/24=3,060
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To this fraction, you could apply your very good advice:somail wrote:
18*17*16*15
___________
4*3*2*1
73,440/24=3,060
For example, you can cancel the 4 with the 16, the 3 with the 15, and the 2 with the 18 to get:somail wrote:NOt really, but you can quicken things by cancelling
9*17*4*5
Now notice how far apart the answer choices are; estimation will easily get us the answer. As long as you can see quickly that this number is a lot larger than 1260, you don't need to do this (rather annoying) multiplication in full. 9*17*4*5 is not far from 10*20*4*5 = 4000, so E must be the right answer.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com
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