If the prime numbers p and t are the only prime factors of the integer m, is m a mutiple of (p^2)*t
1. m has more than 9 positive factors
2. m is a mutiple of p^3
Statement 1 is sufficient
Statement 2 is sufficient
Statement 1 and Statement 2 togethet are sufficient
Either Statement alone is sufficient
Neither Statment is sufficient
Can you please confirm the answer.
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- eagleeye
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B is correct.anks17 wrote:If the prime numbers p and t are the only prime factors of the integer m, is m a mutiple of (p^2)*t
1. m has more than 9 positive factors
2. m is a mutiple of p^3
Can you please confirm the answer.
We are told that m has p and t as the only prime factors. This means that all factors of m (other than 1) are either multiples of p or t. The number of factors will depend on the powers of p and t in m. With this in mind, lets look at the statements.
1. m has more than 9 positive factors
If m = p^5 * t, m will be a multiple of p^2 * t
If m = t^5 * p, m will not be a multiple of p^2 * t
Insufficient.
2. m is a mutiple of p^3
If m is a multiple of p^3, it definitely has p^2 as a factor. Since t is already a factor (from question stem), m is definitely a multiple of p^2 * t. Sufficient.
B is correct.
Last edited by eagleeye on Thu Aug 09, 2012 7:40 pm, edited 1 time in total.