Gmat Prep Good one..

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Gmat Prep Good one..

by btgyes » Thu Feb 24, 2011 6:24 am
..
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by maihuna » Thu Feb 24, 2011 6:33 am
Make a tabular entry, ly, ln, by, bn, where y means yes, n means no, and l, b and are beans

ly ln
by x
bn 2/5
1/3 2/3

so we have to find x = (2/3-2/5)*T = (2/15)*T where T is total studs

1. Given T we can find x

2. given 1/3 of l = 40 => T = 120 same as above so can be found

D
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by Night reader » Thu Feb 24, 2011 6:46 am
hi :)
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by btgyes » Thu Feb 24, 2011 7:22 am
Thanks Mainhuna and Night Reader...

i understood the given table but am still struggling to interpret the meaning of line...

How many of student who LIKE BRU BUT DISLIKE LIMA ?

liking and disliking of both ie BRU and LIMA are in different rows.
so how we can find such thing..

what i find from table is that -> 72 (LIKE BRU) - 80 (DISLIKE LIMA) = -8

i dont know whether it is correct or not.. but even if it is correct am not sure how i can subtract this way (as both are in different rows)

plz clarify with EXACT ANS.

Thanks a lot...!

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by Night reader » Thu Feb 24, 2011 8:35 am
good question might be worthy some kudos ;)
in this case we are not interested in "How many students WHO like brussels sprouts AND dislike Lima beans?" - we are interested in question: "How many students like brussels sprouts BUT dislike Lima beans?". So you just combine two sets and derive the number lying between two sets 72.

If the question would ask "How many students WHO like brussels sprouts AND dislike Lima beans?" then we had to select answer E, because are not availing information about the relationship between two independent sets - Students who like or dislike Brussels sprouts and Students who like or dislike Lima beans.

:)
btgyes wrote:Thanks Mainhuna and Night Reader...

i understood the given table but am still struggling to interpret the meaning of line...

How many of student who LIKE BRU BUT DISLIKE LIMA ?

liking and disliking of both ie BRU and LIMA are in different rows.
so how we can find such thing..

what i find from table is that -> 72 (LIKE BRU) - 80 (DISLIKE LIMA) = -8

i dont know whether it is correct or not.. but even if it is correct am not sure how i can subtract this way (as both are in different rows)

plz clarify with EXACT ANS.

Thanks a lot...!
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Last edited by Night reader on Thu Feb 24, 2011 8:38 am, edited 1 time in total.
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by maihuna » Thu Feb 24, 2011 8:38 am
See your rows should be yes and no row, so all four combinations will be already there : yy, yn, ny, nn

Here u need ByLn you can find in intersection of By and Ln. The actual substraction here will be either from Ln or By.

Try to make the table and do let me know if u still face this issue.


btgyes wrote:Thanks Mainhuna and Night Reader...

i understood the given table but am still struggling to interpret the meaning of line...

How many of student who LIKE BRU BUT DISLIKE LIMA ?

liking and disliking of both ie BRU and LIMA are in different rows.
so how we can find such thing..

what i find from table is that -> 72 (LIKE BRU) - 80 (DISLIKE LIMA) = -8

i dont know whether it is correct or not.. but even if it is correct am not sure how i can subtract this way (as both are in different rows)

plz clarify with EXACT ANS.

Thanks a lot...!
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by GMATGuruNY » Thu Feb 24, 2011 10:18 am
Of the students who eat in a certain cafetaria, each student either dislikes or likes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

1. 120 students eat in the cafeteria
2. 40 of the students like lima beans.
Whenever a problem has two groups (in this case, those who like lima beans and those who don't) further divided into smaller groups (in this case, those who like brussels sprouts and those who don't), we can use the group grid to organize the information:

Image

In the grid above, every row has to add up to the total, as does every column. Looking at the top row, (like brussels and like limas) + (like brussels but dislike limas) = total who like brussels. Looking at the left-most column, (like limas and like brussels) + (like limas but dislike brussels) = total who like limas.

Let T = total students. Thus, the bottom right corner = T.

2/3 dislike lima beans:
Thus, the bottom of the middle column = (2/3)T.
Since the sum of the bottom row is T, the bottom of the leftmost column (the total who like limas) = (1/3)T.

Of those who dislike lima beans, 3/5 also dislike brussels sprouts.
Thus, the middle box = (3/5)(2/3)T.
Since the sum of the middle column is (2/3)T, the top box of the middle column (the total who dislike limas but like brussels sprouts) = (2/5)(2/3)T.

Thus, to determine the number who like brussels sprouts but dislike lima beans, we need to know the value of T.

Statement 1: 120 students eat in the cafeteria
T = 120.
Sufficient.

Statement 2: 40 students like lima beans
The bottom left corner shows that the number who like limas = (1/3)T.
Thus, (1/3)T = 40.
T = 120.
Sufficient.

The correct answer is D.
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by btgyes » Thu Feb 24, 2011 10:39 pm
Brilliant..Brilliant...Brilliant Guys.....!


i got it exactly where i was doing mistake...

I made table in such a way -> Like Dislike Total
Lima

Bru

Total Silly way.. :) so was getting strange combination..:)


IN PLACE OF

Like Lima Dislike Lima Total
Like Bru

Dislike Bru

Total

which is the PERFECT... !

Thanks a lot Guys...!