gmatrant wrote:I got this problem wrong again while I took the test..
Thought Ill repost, then decided to update this old post.
Can anyone comment how functions related problems are to be addressed.
In the above case as pointed by Suyog, why not A as the answer?
I tend to just plug in numbers to the given function to see what its really saying, rather than interpreting the sometimes cryptic function statements.
So for this question you plug in 1 (randomly chosen, but a good starting point) for x then we get f(1)=f(1-1)=f(0). So it's saying f(1) must equal f(0).
So now you goto the answers and plug in 1 and 0 to see if one equation yields the same answer.
So when you plug in 1 into function A, [f(x)=1-x] f(1)=1-1=0
and from above you know that f(1) must equal f(0), so now try 0 in the equation. f(0)=1-0=1 So 1 /= 0 so A doesn't work.
Now onto D, [f(x)=x^2(1-x)^2] f(1)=0 and f(0)=0. This works but I would try two other numbers just to be sure. So f(2) and f(1-2)=f(-1).
f(2)=4 and f(-1)=4 so D does work.