GMAC Practice Exam PS question

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 91
Joined: Mon Dec 31, 2007 4:54 pm
Location: Houston
Thanked: 1 times

GMAC Practice Exam PS question

by smar83 » Sun Feb 10, 2008 4:08 pm
This can be solved by a long method, but any shorter way under time constraint ?
Attachments
untitled1.zip
(30.68 KiB) Downloaded 104 times

Junior | Next Rank: 30 Posts
Posts: 18
Joined: Wed Jan 30, 2008 8:50 pm

what is the answer?

by meghamehta15 » Sun Feb 10, 2008 4:47 pm
what is the Official Answer? Is it a ? 7?

Senior | Next Rank: 100 Posts
Posts: 91
Joined: Mon Dec 31, 2007 4:54 pm
Location: Houston
Thanked: 1 times

by smar83 » Sun Feb 10, 2008 4:48 pm
yea, it is A.

Senior | Next Rank: 100 Posts
Posts: 91
Joined: Mon Dec 31, 2007 4:54 pm
Location: Houston
Thanked: 1 times

by smar83 » Sun Feb 10, 2008 4:52 pm
Can you please explain ?

Junior | Next Rank: 30 Posts
Posts: 18
Joined: Wed Jan 30, 2008 8:50 pm

by meghamehta15 » Sun Feb 10, 2008 5:12 pm
Harvesting machine H harvested 40 acres of wheat in 8 hours

so it harvested 40/8= 5 acres in one hour.


then the machine K was brought in. Together they harvested the rest in 5 hours. so 100-40=60 acres in 5 hours. So together they harvested in 12 hours.

So machine K's rate was 12 hours together-5hours H's rate= 7 hours.

Note: I suppose that when they both worked together, the time taken did not decrease like in other work problems which is why we didn't take the usual 1/5+1/x=1/12..

Senior | Next Rank: 100 Posts
Posts: 91
Joined: Mon Dec 31, 2007 4:54 pm
Location: Houston
Thanked: 1 times

by smar83 » Sun Feb 10, 2008 5:31 pm
Thanks, I got it now. I took the usual 1/x+1/5 like we do for each of the work problems. But the key is 1/5 is work done in 1 hour.

Thanks Megha.

Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Mon Feb 11, 2008 6:18 pm
Location: USA

by subbu123 » Mon Feb 11, 2008 6:50 pm
Hi,

Though the answer is 7 acres per hr. I believe the approach is this.

First information H completing 40 acres in 8 hrs is used in finding out H's speed i.e 5 acres per hour.

In the second set of information H and K together finished the work in 5 hrs

We know that had H worked alone, he would have completed 60 acres in 12 hrs.

so
1/5 = 1/12 + 1/K gives you k's time ie 60/7 hrs and hence K's speed is 60/60/7 ie 7 acres per hour

Legendary Member
Posts: 789
Joined: Sun May 06, 2007 1:25 am
Location: Southern California, USA
Thanked: 15 times
Followed by:6 members

work formula

by resilient » Tue Feb 12, 2008 12:38 am
the work formula actually makes this hard and MegaMehta made an awesome approach to this question.
Appetite for 700 and I scraped my plate!

Junior | Next Rank: 30 Posts
Posts: 19
Joined: Wed Feb 06, 2008 9:22 am

by gmatjoe » Tue Feb 12, 2008 11:18 am
I solved it this way, may ad another view, but logic is similar to earlier posts:
1) K harvested 40 acres, so there is (100-40=) 60 acres left.
2) Rate of K is 40/8 = 5 acres/hr
3) Its given that 5hrs is needed for K & H to harvest the rest (=60 acres)
4) with 2) H needed to harvest (60-25=) 35 acres in 5hrs, hence H needed 7hrs.

Good luck,

Joe.