It is a very simple question.
According to statement (1), n is a multiple of 20.
i.e n = 20x, where x = ....-3, -2, -1, 0, 1, 2, 3......
So n = .....-60, -40, -20, 0, 20, 40, 60,.....
But still n can be and can not be multiple of 15. Hence, Statement (1) is alone insufficient. Therefore, (A) and (D) are out.
According to statement (2), n+6 is multiple of 3.
i.e. (n+6) = 3x, where x = ....-3, -2, -1, 0, 1, 2, 3......
So n = .....--3, 0, 3, 6, 9, 12, 15, 18, 21,..30, 60, 90
But still n can be and can not be multiple of 15. Hence, Statement (2) is alone insufficient. Therefore, (B) is also out
Now lets take both the statements together,
So, -40, -20, 20, 40 etc are out. and only with n = ....-120, -60, 0, 60, 120....
Which is multiple of 15. Hence, both statements together are sufficient.
HTH...