-2<x<4?
a.|x-2|<4
b.|x-1|<3
c.|x+1|<3
d.|x+2|<4
e. none of the above
OA:d
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-2<x<4
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Approach from Answer choices and use definitionshibal wrote:-2<x<4?
a.|x-2|<4
b.|x-1|<3
c.|x+1|<3
d.|x+2|<4
e. none of the above
OA:d
a. -2<x-2<4 add 2 to both sides to get x in middle
0 < No.
b. -3 < x-1<3. Add 1
-2 < x<4 Yes. . Correct answer is B.
d. -4 < x+2<4. Add -2
-6<x<-2. No. OA wrong.
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artistocrat
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maihuna
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such Q requires dividing the two sides equally and substracting the half of that from x
4-(-2) = 6
6/2 = 3
so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
4-(-2) = 6
6/2 = 3
so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
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shibal
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what do you mean by dividing them equally? average????maihuna wrote:such Q requires dividing the two sides equally and substracting the half of that from x
4-(-2) = 6
6/2 = 3
so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
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maihuna
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The numerical values on either side of the modulus needs to be same, albeit with opposite sign, i.e -3<x<3, so fins the range of those number and divide them by 2 to get the equal no, and then suitably substract it from the mod vsar...hope it clarifies...shibal wrote:what do you mean by dividing them equally? average????maihuna wrote:such Q requires dividing the two sides equally and substracting the half of that from x
4-(-2) = 6
6/2 = 3
so each side requires 3: -2-1<x-1<4-1 or -3<x-1<3 or |x-1|<3
Charged up again to beat the beast
