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GCD

Expert replies
by nipunranjan » Thu Aug 15, 2013 9:16 am
If x and y are positive integers such that x=8y+12, what is the greatest common divisor of x and y.
1. y=12m, where m is an integer.
2. x= 12n, where n is an integer.

OA=A
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Source: — Data Sufficiency |

by GMATGuruNY » Thu Aug 15, 2013 9:33 am
If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y?

(1) x = 12u, where u is an integer
(2) y = 12z, where z is an integer

OA is B
For many test-takers, the most efficient approach on test day would be to plug in values.

Statement 1: x=12u, where u is an integer and x=8y+12.
In other words, x is a multiple of 12.
For x to be a multiple of 12, 8y must be a multiple of 12.

If y=3, then x = 8*3 + 12 = 36.
The GCD of 3 and 36 is 3.

If y=6, then x = 8*6 + 12 = 60.
The GCD of 6 and 60 is 6.

Since the GCD can be different values, INSUFFICIENT.

Statement 2: y=12z, where z is an integer and x=8y+12.
In other words, y is a multiple of 12.
Since we're looking for the GCD, view x in terms of its FACTORS.

If y=12, then x = 8(12) + 12 = 12(8+1) = 12*9.
The GCD of 12 and 12*9 is 12.

If y=24, then x = 8(24) + 12 = 12(8*2 + 1) = 12*17.
The GCD of 24 and 12*17 is 12.

I'm almost convinced: the GCD is 12.
Maybe one more just to be sure:

If y=36, then x = 8(36) + 12 = 12(8*3 + 1) = 12*25.
The GCD of 36 and 12*25 is 12.
SUFFICIENT.

The correct answer is B.
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by Brent@GMATPrepNow » Thu Aug 15, 2013 2:29 pm
nipunranjan wrote:If x and y are positive integers such that x = 8y + 12, what is the greatest common divisor of x and y.
1. y = 12m, where m is an integer.
2. x = 12n, where n is an integer.

OA=A
This question is very similar to an official GMAT question. Mitch has inadvertently answered the other question.

One solution to the question you have posed is as follows:

Target question: What is the greatest common divisor of x and y?

Given: x = 8y + 12

Statement 1: y = 12m, where m is an integer
If y = 12m and x = 8y + 12, then we can replace y with 12m to get:
x = 8(12m) + 12, which means x = 96m + 12, which means x = 12(8m + 1) [if we factor]
So, rather than ask "What is the GCD of x and y?", we can ask "What is the GCD of 12m and 12(8m + 1)?"
Well, we can see that they both share 12 as a common divisor, but what about m and 8m+1?
Well, there's a nice rule that says: If n and k are positive integers, the GCD of n and kn+1 is always 1
So, the GCD of m and 8m+1 is 1, which means the GCD of 12m and 12(8m + 1) is 12.
This means that the GCD of x and y is 12
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: x = 12n, where n is an integer.
There are several pairs of values that satisfy the given conditions. Here are two:
Case a: x=36 and y=3, in which case the GCD of x and y is 3
Case b: x=60 and y=6, in which case the GCD of x and y is 6
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Java_85 » Thu Aug 15, 2013 3:53 pm
I think A is the answer.

1) x=12(8m+1) & y = 12m ==> 12
2) x=12n & y=12/8 (n-1) ==> We can't say

Then, A it is.
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