51. How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3?
A.14 B.15. C.16 D.17 E.18
The OA is 16 with following explanation. But I think its wrong because its missing 1. So correct answer should be 17. What do you think ?
Soln: if we arrange this in AP, we get
4+7+10+.......+49
so 4+(n-1)3=49: n=16
C is my pick
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wilderness
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parallel_chase
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The OA should be 17
1 has to be included simply because when 1 is divided by 3 it gives remainder 1.
1 has to be included simply because when 1 is divided by 3 it gives remainder 1.
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malolakrupa
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Right but the problem asks for REMAINDERS of 1 when divided by 3. So if we go back to the general eqn for a number of N=QD+r and rearrange to express as N/D=Q+D/D we find that 1=0*3+r (r=1) or to rearrange in other form of 1 divided by 3 --> 1/3 = 0 + 1/3....you can see you get a remainder of 1
N=number
Q=quotient
D=divisor
r=remainder
N=number
Q=quotient
D=divisor
r=remainder
