finite

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finite

by ST » Mon Aug 10, 2009 5:49 am
Could someone please explain this?
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by real2008 » Mon Aug 10, 2009 9:22 am
it is D

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by Gopi » Tue Aug 18, 2009 8:49 pm
Each term after second term is sum of two terms immediately preceding terms
=> K3=k2+k1
k4=k3+k2
k4=k2+k1+k2
k4=2k2+k1

//y k5=3k2+2k1

so the terms in the sequence can be generalized in the form of Kn=k2 + (n-3)(k2+k1)

=>K9=k2+6(k1+k2)
and K5=K2+2(k1+k2)


statement 1

K4=11
we know k5 and k4 (this is nothing but two different first degree equations with two unknowns) and hence we can find k1, K2 and thus k9

so statement 1 alone is sufficient

Statement 2
following the same logic as above we can find out k9

so statement 2 alone is sufficient


Hence the answer is D

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by tohellandback » Tue Aug 18, 2009 9:26 pm
IMO D
we have K5
1) given K4- we can find K6,K7 and so on
SUFFICIENT

2) given K6- using K5 and K6 we can find K7..and so on
SUFFICIENT
The powers of two are bloody impolite!!