If 5^(6x) = 125,000 Then, 5^(2x−1) = ?
5^6x= 5^3 10^3
(5^6x) - (5^3) =10^3
so ((5^6x) - (5^3))/3 = 10^3/3
I think i am on the right track and need to tie this up!
qa 10
Source is GuruGuide and its an advanced question.
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factor problem
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simba12123
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Last edited by simba12123 on Mon Nov 03, 2008 8:33 pm, edited 3 times in total.
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stubbornp
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5^6x= 5^3 10^3simba12123 wrote:If 5^(6x) = 125,000 Then, 5^(2x−1) = ?
5^6x= 5^3 10^3
(5^6x) - (5^3) =10^3
so ((5^6x) - (5^3))/3 = 10^3/3
I think i am on the right track and need to tie this up!
qa 10
Source is GuruGuide and its an advanced question.
(5^6x)/5^3=10^3
5^(6x-3)=10^3
5^(2x-1)3=10^3
taking cube root both sides
5^(2x-1)=10...hope it clears
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cramya
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Nice work stubbornp!
5^(6x-3)=10^3 Got up to here and dint have an answer after that for Simba
When u did 5 ^ ((2x-1) * 3)) are u doing a^(b*c) = (a^b) ^ c to get to
(5 ^ (2x-1)) ^ 3 i.e where a=5 b = 2x-1 c=3
Let me know!
5^(6x-3)=10^3 Got up to here and dint have an answer after that for Simba
When u did 5 ^ ((2x-1) * 3)) are u doing a^(b*c) = (a^b) ^ c to get to
(5 ^ (2x-1)) ^ 3 i.e where a=5 b = 2x-1 c=3
Let me know!
Nice work stubbornp!
5^(6x-3)=10^3 Got up to here and dint have an answer after that for Simba
When u did 5 ^ ((2x-1) * 3)) are u doing a^(b*c) = (a^b) ^ c to get to
(5 ^ (2x-1)) ^ 3 i.e where a=5 b = 2x-1 c=3
u can write 5 ^ ((2x-1) * 3)) as 5^ 3 * ((2x-1))..
and cube root of 5^ 3*(2x-1) = 5 ^ 2x-1
i hope it helps...
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logitech
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5^(2x−1), simply means: 5^2x/5simba12123 wrote:If 5^(6x) = 125,000 Then, 5^(2x−1) = ?
5^6x= 5^3 10^3
(5^6x) - (5^3) =10^3
so ((5^6x) - (5^3))/3 = 10^3/3
I think i am on the right track and need to tie this up!
qa 10
Source is GuruGuide and its an advanced question.
So we should hunt for 5^2x
since If 5^(6x) = 125,000 = 5^3 10^3 ( EASY TO SPOT )
5^2x = 5 x 10
Therefore, 5^2x/5 = 10
Another way to think a problem is always good!
LGTCH
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