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f, m and n

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Source: — Data Sufficiency |
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by ontopofit » Fri Feb 20, 2009 11:50 am
IMO A

1) when n+45/n,rem= 12....so,n can be 45-12 = 33....here it cannot be 11 since rem is always < the divisor...hence 33

2) n is odd, insuff
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by DanaJ » Fri Feb 20, 2009 11:52 am
ontopofit: what if you take n = 57?
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by ontopofit » Fri Feb 20, 2009 12:00 pm
then f(n + 45) will be 45 and not 12.

57+45/57,rem = 45
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by DanaJ » Fri Feb 20, 2009 12:06 pm
Yes, you are right... Sorry....
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by cramya » Fri Feb 20, 2009 9:19 pm
Stmt I

n+45 / n = Q + 12 where Q is the quotient

n+45 = nq+12

n(q-1) = 33

n has to be less than 15

SUFF

Stmt II

n is odd

n=7,17... etc many possible values

I agree with A
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by sureshbala » Fri Feb 20, 2009 9:44 pm
cramya wrote:Stmt I

n+45 / n = Q + 12 where Q is the quotient

n+45 = nq+12

n(q-1) = 33

n has to be less than 15

SUFF

Stmt II

n is odd

n=7,17... etc many possible values

I agree with A
Hi, I think you have to check the bold statement above.

n(q-1) = 33.

Also since the remainder in 12, n must be greater than 12.

hence the only value for n is 33.

So n>15.
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