If 5^21 * 4^11 = 2 * 10^n , what is n?
a. 11
b. 21
c. 22
d. 23
e. 32
OA: B
Please give a detailed explanation of how to solve.
Thanks!
Exponents
This topic has expert replies
Thanks again! You are awesome!papgust wrote:5^21 * 4^11 = 2 * 10^n
5^21 * 2^22 = 2 * 2^n * 5^n
5^21 * 2^22 = 2^(n+1) * 5^n
I had gotten it as far as I bolded above, but I did not know how to compare the two different things, now I know you can split them out separately.
Thanks!
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In these problems, we try to make the bases equivalent. After that, somerules you will have to use commonly are:chipbmk wrote:If 5^21 * 4^11 = 2 * 10^n , what is n?
a. 11
b. 21
c. 22
d. 23
e. 32
OA: B
Please give a detailed explanation of how to solve.
Thanks!
(a^b)^c = a^b*c; and
a*c * b*c = (a*b)^c (when you have the same exponents, you can "group" the bases together and raise them to the common exponent)
5^21 * 4^11 = 2 * 10^n
5^21 * (2^2)^11 = RHS
5^21 * 2^22 = RHS
5^21 * 2^21 * 2^1 = RHS
(5*2)^21 * 2^1 = RHS
2 * 10^21 = 2*10^n
21 = n
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