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Exponents problem from the official practice test

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Junior | Next Rank: 30 Posts
Posts: 26
Joined: Fri Apr 06, 2007 10:40 am

Exponents problem from the official practice test

by sev » Wed Jun 06, 2007 11:59 am
(1/5)^m (1/4)^18 = 1/2(10)^35

answers are:

17
18
34
35
36

how the heck do you solve this?
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Junior | Next Rank: 30 Posts
Posts: 15
Joined: Mon Nov 27, 2006 4:55 pm

by sudhirsk » Wed Jun 06, 2007 8:23 pm
(1/5)^m (1/4)^18 = 1/2(10)^35

answers are:

17
18
34
35
36


(1/5)^m * (1/4)^18 = 1/2 * 1/(5*2)^35
= 1/2 * (1/2)^35 * (1/5)^35
(1/5)^m * (1/2)^36 = (1/2)^36 * (1/5)^35
Hence m =35
What is the OA?
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Newbie | Next Rank: 10 Posts
Posts: 2
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Location: India

by murkrish » Thu Jun 07, 2007 7:48 am
sudhirsk wrote:(1/5)^m (1/4)^18 = 1/2(10)^35

answers are:

17
18
34
35
36


(1/5)^m * (1/4)^18 = 1/2 * 1/(5*2)^35
= 1/2 * (1/2)^35 * (1/5)^35
(1/5)^m * (1/2)^36 = (1/2)^36 * (1/5)^35
Hence m =35
What is the OA?
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Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Mon Jun 04, 2007 8:13 am
Location: India

by murkrish » Thu Jun 07, 2007 7:51 am
Even I would go with M=35.

Post the OA.
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Junior | Next Rank: 30 Posts
Posts: 26
Joined: Fri Apr 06, 2007 10:40 am

by sev » Thu Jun 07, 2007 9:50 am
The OA is 35...
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Junior | Next Rank: 30 Posts
Posts: 26
Joined: Fri Apr 06, 2007 10:40 am

by sev » Thu Jun 07, 2007 9:51 am
What would you approximate the difficulty level on the CAT for this problem would be?
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