Need some quick help on this seemingly easy problem:
2^x - 2^(x-2) = 3(2^13) what is x?
the answer is 15.
3? i know im supposed to simplify so that i can just add/subtract exponents. but the [x-(x-2)] seem to be canceling each other out?
any thoughts?
thanks all!
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Exponent problem
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xcusemeplz2009
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simplify is just what we need to do here
2^x-2^(x-2)=2^x-2^x/2^2=2^x(1-1/4)=2^x*(3/4)=2^(x-2)*3
now equate 2^(x-2)*3=(2^13)*3=> x-2=13;x=15
2^x-2^(x-2)=2^x-2^x/2^2=2^x(1-1/4)=2^x*(3/4)=2^(x-2)*3
now equate 2^(x-2)*3=(2^13)*3=> x-2=13;x=15
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viju9162
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2^x - 2^x/4 = 3( 2^13)
2^x( 1-1/4) = 3 ( 2^13)
2^x (3/4) =3( 2^13)
(2^x-2)3 = 3 ( 2^13)
x-2=13; x=15
Hi saracuse,
x-(x-2)doesnt cancel off ... it will be like this : 2^x/2^2 ... then u can follow the above steps...
Hope this helps..
2^x( 1-1/4) = 3 ( 2^13)
2^x (3/4) =3( 2^13)
(2^x-2)3 = 3 ( 2^13)
x-2=13; x=15
Hi saracuse,
x-(x-2)doesnt cancel off ... it will be like this : 2^x/2^2 ... then u can follow the above steps...
Hope this helps..
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