is |xy| > x^2y^2?
1. 0<x^2<1/4
2. 0<y^2<1/9
in this question C looks like an obvious answer. But how do we recognize statement 1 and 2 not eing sufficient by itself? Other than "statement 1 says nothing about Y, so it can't be sufficient. We can't assume that all the time. How do we recognize in statement 1 and 2 that it is not enough.
THis question came as a "hard" question so since C was so obvious I was scared to pick it. I hate to brute force statements 1 and 2 because it gets so annoying and stressful during a timed exam.
Perhaps there is a way to simply this question?
example number properties DS
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- aneesh.kg
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Oh yes, no need of brute force.
The question is:
Is |xy| > (x^2)(y^2)?
Thought No. 1: Both LHS and RHS are positive quantities. Hmm.
Thought No. 2: Oh! We're squaring x and y on the RHS. That would mean that the RHS has really large quantities.
Thought No. 3: When will this inequality hold true then?
Thought No. 4: Um, when we square a number between -1 and 1, that is if |n| < 1, then n^2 < |n|. For example if you square (1/2) or (-1/2), it becomes 1/4.
Thought No. 5: So, |xy| > x^2y^2, when -1 < x < 1 AND -1 < y < 1. If any one of x or y exceeds 1, the RHS will become really large and the inequality will not hold true.
Thought No. 6(and now we look at the statements): If only 0 < x < 1, but y > 1 then the RHS may become larger than LHS. If 0 < y < 1, but x > 1, then the RHS may become larger than LHS. Both the Statements together tell us that x and y are small fraction quantities. The given inequality will hold true when they are combined.
[spoiler](C)[/spoiler] is the answer.
By the way, what would your answer have been if the Statements were:
Statement(1): 1 < x < 3/2
Statement(2): 4/3 < y < 7/4
?
The question is:
Is |xy| > (x^2)(y^2)?
Thought No. 1: Both LHS and RHS are positive quantities. Hmm.
Thought No. 2: Oh! We're squaring x and y on the RHS. That would mean that the RHS has really large quantities.
Thought No. 3: When will this inequality hold true then?
Thought No. 4: Um, when we square a number between -1 and 1, that is if |n| < 1, then n^2 < |n|. For example if you square (1/2) or (-1/2), it becomes 1/4.
Thought No. 5: So, |xy| > x^2y^2, when -1 < x < 1 AND -1 < y < 1. If any one of x or y exceeds 1, the RHS will become really large and the inequality will not hold true.
Thought No. 6(and now we look at the statements): If only 0 < x < 1, but y > 1 then the RHS may become larger than LHS. If 0 < y < 1, but x > 1, then the RHS may become larger than LHS. Both the Statements together tell us that x and y are small fraction quantities. The given inequality will hold true when they are combined.
[spoiler](C)[/spoiler] is the answer.
By the way, what would your answer have been if the Statements were:
Statement(1): 1 < x < 3/2
Statement(2): 4/3 < y < 7/4
?
Aneesh Bangia
GMAT Math Coach
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GMAT Math Coach
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GMATPad:
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- dabral
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