If a and b are positive integers such that a – b and a/b are both even integers, which of the following must be an odd integer?
A. a/2
B. b/2
C. (a+b) /2
D. (a+2) /2
E. (2+b) /2
even integer
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a-b is an even integer
This is possible only when a and b both are either even or odd
i.e. a = 10 and b = 4
or a = 9 and b = 5
a/b is an even integer
Since we can have both odd or both even a/b is even only when a and b, both are even...
Now from the ans choices...
(a+b) / 2 will provide the odd ans..
Ans C.
This is possible only when a and b both are either even or odd
i.e. a = 10 and b = 4
or a = 9 and b = 5
a/b is an even integer
Since we can have both odd or both even a/b is even only when a and b, both are even...
Now from the ans choices...
(a+b) / 2 will provide the odd ans..
Ans C.
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The best strategy is to pick numbers
Since its a must question try plugging in more than 3 values for a and b
I think the answer is D because for all other values there is a yes and a no as an answer
The answer is not C because lets assume a=8 and b=4 then (a+b)/2=12/2=6 which is an even number.
Is the answer D??
Since its a must question try plugging in more than 3 values for a and b
I think the answer is D because for all other values there is a yes and a no as an answer
The answer is not C because lets assume a=8 and b=4 then (a+b)/2=12/2=6 which is an even number.
Is the answer D??
Maxx
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can't the answer also be E since 4+2=6 and 6/2=3?moneyman wrote:The best strategy is to pick numbers
Since its a must question try plugging in more than 3 values for a and b
I think the answer is D because for all other values there is a yes and a no as an answer
The answer is not C because lets assume a=8 and b=4 then (a+b)/2=12/2=6 which is an even number.
Is the answer D??
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If a and b are positive integers such that a ? b and a/b are both even integers, which of the following must be an odd integer?
a-b is even so both a& b are either odd or even
a/b is even, possible only if both are even(considering the above case also into account)
so we can say that both a & b are even numbers
also a/b =c (c is even) i.e a = bc
now we have
A a/2 = bc/2 is even ( both b & c have 2 as a factor)
B. b/2 = odd or even
C. (a+b) /2 = (bc + b)/2 = b(c+1)/2 (may be even or odd)
D. (a+2) /2 = a/2 + 1 = even nos + 1 = odd
E. (2+b) /2 = 1 + b/2 (b/2 can be both even as well as odd)
a-b is even so both a& b are either odd or even
a/b is even, possible only if both are even(considering the above case also into account)
so we can say that both a & b are even numbers
also a/b =c (c is even) i.e a = bc
now we have
A a/2 = bc/2 is even ( both b & c have 2 as a factor)
B. b/2 = odd or even
C. (a+b) /2 = (bc + b)/2 = b(c+1)/2 (may be even or odd)
D. (a+2) /2 = a/2 + 1 = even nos + 1 = odd
E. (2+b) /2 = 1 + b/2 (b/2 can be both even as well as odd)
Regards
Samir
Samir
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a - b = 2m where m GE 0. --(1)
a = 2qb where q GE 0 -- (2)
From (2) a is even. Hence b is also even from (1).
now (a + 2)/2 = (2qb + 2)/2 = qb + 1
b is even implies qb is even implies qb + 1 must be ODD.
Hence (a+2)/2 is odd.
Calista.
a = 2qb where q GE 0 -- (2)
From (2) a is even. Hence b is also even from (1).
now (a + 2)/2 = (2qb + 2)/2 = qb + 1
b is even implies qb is even implies qb + 1 must be ODD.
Hence (a+2)/2 is odd.
Calista.