What is the value of x?
(1) 3(x–1) = y+3x
(2) (x+2)(y+3) = 0
Answer: E
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Brent@GMATPrepNow
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cramya
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Stmt I
3(x-1) = y+3x
3x-3 = y+3x
y=-3
No way to find X
INSUFF
Stmt II
(x+2)(y+3) = 0
Either x ix-2 or y is -3 or they both can be -2 and -3
INSUFF
Stmt I and II together
y=-3
Still we dont know if x is -2 or any other value
INSUFF
Choose E)
3(x-1) = y+3x
3x-3 = y+3x
y=-3
No way to find X
INSUFF
Stmt II
(x+2)(y+3) = 0
Either x ix-2 or y is -3 or they both can be -2 and -3
INSUFF
Stmt I and II together
y=-3
Still we dont know if x is -2 or any other value
INSUFF
Choose E)
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logitech
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(1) 3(x–1) = y+3x
3x cancels. no info for X INSUF
(2) (x+2)(y+3) = 0
X=-2 or y=-3 INSUF
(1)+(2)
Can not be solved for X because there is no X values in statement 1
Choose E
3x cancels. no info for X INSUF
(2) (x+2)(y+3) = 0
X=-2 or y=-3 INSUF
(1)+(2)
Can not be solved for X because there is no X values in statement 1
Choose E
LGTCH
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vittalgmat
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parallel_chase
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Yes thats correctvittalgmat wrote:in stmt 1 we cant find value of x.
Is it coz x can potentially have infinite values??
thanks
3(x–1) = y+3x
3x - 3 = y + 3x
y = -3
substitute value of y back in the equation
3x - 3 = -3 + 3x
LHS = RHS
Therefore, any value of x will satisfy the equation. Hence, we cannot get a single value of x.
No rest for the Wicked....
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4meonly
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Brent, GIVE US MORE NEW TOUGH QUESTIONS!!!!Brent Hanneson wrote:What is the value of x?
(1) 3(x–1) = y+3x
(2) (x+2)(y+3) = 0
Answer: E
Your questions are very interesting. I solved all questions from your site
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vittalgmat
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I second that!!!4meonly wrote:Brent, GIVE US MORE NEW TOUGH QUESTIONS!!!!Brent Hanneson wrote:What is the value of x?
(1) 3(x–1) = y+3x
(2) (x+2)(y+3) = 0
Answer: E
Your questions are very interesting. I solved all questions from your site
Yeah.. Brent pllllllllleeeeeeaaaaase give us new tough questions.. I love your your approach to solutions as well...
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ronniecoleman
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schumi_gmat
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This a good question.
I have one question regarding stmt B.
from B, we know x=-2 and y=-3
Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y?
I have one question regarding stmt B.
from B, we know x=-2 and y=-3
Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y?
Cramya wrote:
Stmt II
(x+2)(y+3) = 0
Either x ix-2 or y is -3 or they both can be -2 and -3
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Brent@GMATPrepNow
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Actually, there are an infinite number of solutions to the equation (x+2)(y+3) = 0I have one question regarding stmt B.
from B, we know x=-2 and y=-3
Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y?
Quote:
Cramya wrote:
Stmt II
(x+2)(y+3) = 0
Either x ix-2 or y is -3 or they both can be -2 and -3
Here are a few:
y = -3 and x=7
y = -3 and x=-4
y = -3 and x=222
y = -3 and x=1,000,000
etc.
If you plug in these values, it is true that (x+2)(y+3) = 0
Since x can have an infinite number of values, we can't definitively say what x is.
I hope that helps.
Brent Hanneson - Creator of GMATPrepNow.com
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iamcste
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schumi_gmat wrote:This a good question.
I have one question regarding stmt B.
from B, we know x=-2 and y=-3
Are we discarding B, because there are 2 solns for the equations regardless of we have unique values of x and y?
Cramya wrote:
Stmt II
(x+2)(y+3) = 0
Either x ix-2 or y is -3 or they both can be -2 and -3
eqtn is satisifed if
1. x=-2, y=irrespective, or
2. y=-3, x=irrespective, or
3. x=-2 and y=-3
so, we dont know exact value of x ( from above, it may be -2 or any other value when y=-3)
Insufficient
