elements in Set A, B and C

This topic has expert replies
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Sun Nov 29, 2009 7:26 am

elements in Set A, B and C

by nirajanshrestha » Mon Dec 14, 2009 5:48 am
Set A, B and C have some elements in common. If 16 elements are in both A and B, 17 elements are in both A and C, and 18 elements are in both B and C, how many elements do all these three of the sets A, B and C have in common?

1. Of the 16 elements that are both in A and B, 9 elements are also in C.
2. A has 25 elements, B has 30 elements and C has 35 elements.

Master | Next Rank: 500 Posts
Posts: 168
Joined: Mon Apr 13, 2009 6:48 pm
Thanked: 6 times

by punitkaur » Mon Dec 14, 2009 11:37 am
IMO A.

1. right away gives A & B & C = 7 - sufficient

2. For this one we need the total no of elements in A,B,C (A U B U C) to calculate A&B&C. - not sufficient

Legendary Member
Posts: 1161
Joined: Mon May 12, 2008 2:52 am
Location: Sydney
Thanked: 23 times
Followed by:1 members

by mehravikas » Mon Dec 14, 2009 7:18 pm
I am not too sure - Can we rule out B for the following reasons:

1. It doesn't give the total number of elements
2. It doesn't give the elements that do not belong to A, B and C.

User avatar
Senior | Next Rank: 100 Posts
Posts: 45
Joined: Sun Dec 28, 2008 2:17 am
Location: lahore, pakistan

by hamxa » Thu Mar 11, 2010 3:30 am
@ punitkaur

You mean 9 elements in common ?

User avatar
Master | Next Rank: 500 Posts
Posts: 233
Joined: Mon Jun 09, 2008 1:30 am
Thanked: 5 times

by blaster » Thu Mar 11, 2010 4:58 am
I think IMO is E .

User avatar
Senior | Next Rank: 100 Posts
Posts: 45
Joined: Sun Dec 28, 2008 2:17 am
Location: lahore, pakistan

by hamxa » Thu Mar 11, 2010 8:15 am
the solution by punitkar is on the right lines

this is from gmatprep and OA is A.

User avatar
Legendary Member
Posts: 748
Joined: Sun Jan 31, 2010 7:54 am
Thanked: 46 times
Followed by:3 members

by outreach » Thu Mar 11, 2010 10:37 am
Total = Group1 + Group2 + Group3 - (sum of 2-group overlaps) - 2*(all three) + Neither

opt 1:
all 3 is 9. Sufficient.

opt 2:
Gives us Group1 Group2 & Group3. Unless we know 'Total' and 'neither' this info is useless. Insuff
-------------------------------------
--------------------------------------
General blog
https://amarnaik.wordpress.com
MBA blog
https://amarrnaik.blocked/

Master | Next Rank: 500 Posts
Posts: 194
Joined: Thu Jan 14, 2010 5:18 am
Thanked: 2 times

by girish3131 » Tue Mar 16, 2010 12:22 am
I do not agree at all that A is right ans....

Even if u consider 9 are common among A, B and C

still we dont have any clue that

whether

elements which are common b/w B and C also common with A also.... ?

and

whether

elements which are common b/w C and A also common with B too... ?

without these inf... nothing can be said....


IMO Ans is E

Senior | Next Rank: 100 Posts
Posts: 43
Joined: Sat Mar 13, 2010 4:11 am
Thanked: 1 times

by STEVEN SPIELBERG » Tue Mar 16, 2010 2:01 am
What's the OA ?
I want to win an OSCAR on the GMAT !!!

Senior | Next Rank: 100 Posts
Posts: 75
Joined: Tue Jan 19, 2010 10:43 am

by sarthak » Tue Mar 16, 2010 5:11 am
OA is A

Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Thu Mar 18, 2010 11:53 pm

by cooo3 » Fri Mar 19, 2010 3:31 am
i agree with girish.

can you please explain why you chose A ?

IMO the information about how many elements of AC belong to ABC / how many elements of BC belong to ABC is necessary

Master | Next Rank: 500 Posts
Posts: 117
Joined: Wed Jun 09, 2010 7:02 am

by missrochelle » Fri Aug 27, 2010 7:06 am
can u use a venn diagram for this one? or is that too complicated? with these i am tryig to figure the most efficient way venn diagram vs. AuB formula. what is the formula for example?

set A = A - AUB - AUC ?

User avatar
Legendary Member
Posts: 516
Joined: Mon Nov 02, 2009 6:42 am
Location: Mumbai
Thanked: 14 times
Followed by:1 members
GMAT Score:710

by ankurmit » Fri Aug 27, 2010 8:22 am
Neerj.. can you please ppost solution of this quistion
--------
Ankur mittal