Data Sufficiency

The solution to this problem, which says that statement (2) is sufficient to answer the question seems to be wrong to me.

For example, if we try plugging in numbers
consider that x=-2 and y--3. In this case both statements (1) and (2) are satisfied, but x/y will be 2/3 which is less than 1

And if,

consider that x=3 and y=2. In this case too both statements (1) and (2) are satisfied, but x/y now is 3/2 which is greater than one

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I think that neither statement (1) nor (2), nor a combination of the two statements enables to answer the question accurately. This is a question from the official guide edition 12. You can see that they have given the answer as B. Am I missing something too obvious?

u cant take x=-2 and y=-3 as its given that both x and y are positive!
and for any positive value of x and y if x >y then x/y will always be greater than 1.

Example: since x > y so there exist one positive "z" such that x=y+z

=> x/y = (y+z)/y = 1 + (z>y) which is greater than 1 as both z and y are postive!

Gee, thanks. I really have to do something quickly about my blind spot