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Senior | Next Rank: 100 Posts
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by ukr.net » Sun Dec 02, 2007 6:15 am
There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?

45,000
360,000
364,500
392,000
396,900

ANS C .How to solve this task, what is for 36,000 is given???
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by ri2007 » Sun Dec 02, 2007 7:03 am
HC = 36000 + x

PB = 9x

So 441000 = 36000 + 10x

so 9x = 364500
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by sirikesav » Sun Dec 02, 2007 7:25 am
the equation that can be formed from the question is 36000 + 10x = 441000

x= 40500

actually the no of novels sold = x
no of paperback sold = 9x
hence total novels sold is = 36000 + 10x

so the no of paperback sold = 9*40500=364500

hence answer C
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