Q1 Is 2X-3Y< X2?
(1) 2X - 3Y = -2
(2) X>2 and Y>0
DS
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Is 2X - 3Y < X^2. ( Am I right in assuming it is x^2?)
1) 2X - 3Y = -2
This statement says that 2x-3y is negative. x^2 will always be positive.
Therefore, 2x - 3y < x^2. Sufficient.
2) X >2 and Y>0
Let x = 3 and y = 1
2(3) - 3 (1) = 3
x^2 = 3*3 = 9
3 is less than 9
Let x = 3 and y = 10
2(3) - 3(10) = -24
x^2 = 9
-24 is less than 9
Sufficient.
IMO D)
1) 2X - 3Y = -2
This statement says that 2x-3y is negative. x^2 will always be positive.
Therefore, 2x - 3y < x^2. Sufficient.
2) X >2 and Y>0
Let x = 3 and y = 1
2(3) - 3 (1) = 3
x^2 = 3*3 = 9
3 is less than 9
Let x = 3 and y = 10
2(3) - 3(10) = -24
x^2 = 9
-24 is less than 9
Sufficient.
IMO D)
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Statement 1: 2x-3y = -2tanya161 wrote:Q1 Is 2X-3Y< X2?
(1) 2X - 3Y = -2
(2) X>2 and Y>0
Substituting 2x-3y = -2 into the question stem, we get:
-2 < x²?
Since the least possible value of x² is 0, we know that x² > -2.
SUFFICIENT.
Statement 2: X>2 and Y>0.
Let's rephrase the question stem:
2x - 3y < x²
0 < x² - 2x + 3y
0 < x(x-2) + 3y.
Question stem rephrased: Is x(x-2) + 3y > 0?
Since x>2 and y>0, every value on the lefthand side (x, x-2 and 3y) is positive.
Thus, we know that x(x-2) + 3y > 0.
SUFFICIENT.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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