Hi
Please solve the below given problem
In a rectangular coordinate system,does the line K intersect quadrant II
a)slope of the line is -1\6
b)the y-intercept of K is -6
please suggest which option is correct and why.
Thanks & Regards
DS--Slope of line given\y-intercept given
This topic has expert replies
- Patrick_GMATFix
- GMAT Instructor
- Posts: 1052
- Joined: Fri May 21, 2010 1:30 am
- Thanked: 335 times
- Followed by:98 members
Good question. (1) is sufficient because if a line has a negative slope (meaning it goes up and to the left), it will eventually reach Quadrant II (top left quadrant) no matter how far down & right you begin to draw the line. Remember that lines have an infinite length.
(2) gives us one point of the line which is not in Quadrant II. The line itself could be drawn to touch quadrant II, or to not enter it at all. So (2) is not sufficient.
A is the answer.
To better understand, have a look at a step-by-step video solution: This is GMATPrep question 1293
If you have trouble with this type of question, use the Solutions Engine to identify and study similar questions from GMATPrep
-Patrick
(2) gives us one point of the line which is not in Quadrant II. The line itself could be drawn to touch quadrant II, or to not enter it at all. So (2) is not sufficient.
A is the answer.
To better understand, have a look at a step-by-step video solution: This is GMATPrep question 1293
If you have trouble with this type of question, use the Solutions Engine to identify and study similar questions from GMATPrep
-Patrick
-
- Legendary Member
- Posts: 576
- Joined: Sat Mar 13, 2010 8:31 pm
- Thanked: 97 times
- Followed by:1 members
Let the angle between K and x-axis be A.Then slope is tan(A)
From 1
tan(A)=-1/6 so 90> A>180..hence the line will pass through quadrant II...sufficient
From 2
y-intercept of K is -6 ..but this is not sufficient to comment whether slope is positive or negative..not sufficient
Ans option A
p.s its easy to understand this if we draw the lines.
From 1
tan(A)=-1/6 so 90> A>180..hence the line will pass through quadrant II...sufficient
From 2
y-intercept of K is -6 ..but this is not sufficient to comment whether slope is positive or negative..not sufficient
Ans option A
p.s its easy to understand this if we draw the lines.
"If you don't know where you are going, any road will get you there."
Lewis Carroll
Lewis Carroll
-
- Legendary Member
- Posts: 2326
- Joined: Mon Jul 28, 2008 3:54 am
- Thanked: 173 times
- Followed by:2 members
- GMAT Score:710
Adding on to that:liferocks wrote:Let the angle between K and x-axis be A.Then slope is tan(A)
From 1
tan(A)=-1/6 so 90> A>180..hence the line will pass through quadrant II...sufficient
From 2
y-intercept of K is -6 ..but this is not sufficient to comment whether slope is positive or negative..not sufficient
Ans option A
p.s its easy to understand this if we draw the lines.
If the slope is negative the line has to pass through second & fourth quadrant!!