DS question a Day

This topic has expert replies
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

DS question a Day

by ajith » Mon Oct 30, 2006 3:15 am
DS001

If x is positive, is x>3?

a) (x-1)^2 > 4
b) (x-2)^2 > 9

A) a alone b not sufficient
B) b alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient



Answers In 3 days of time

Senior | Next Rank: 100 Posts
Posts: 87
Joined: Fri Jun 09, 2006 2:47 am
Thanked: 2 times

by rajs.kumar » Mon Oct 30, 2006 9:39 am
E.

First case leads to x > 3 or x > -1 => insufficient
Second case leads to x > 5 or x > -1 => insufficient

Both together is still inconclusive x could be a positive number greater or less or equal to 3.

User avatar
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Wed Jul 12, 2006 3:13 pm
Followed by:4 members

by limits660 » Mon Oct 30, 2006 10:29 am
Is it possible to go step by step in breaking down each condition

Im still a little fuzzy on this one.

thanks
-
Jeff Sacco
www.jeffsacco.ca

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

Re: DS question a Day

by ajith » Mon Oct 30, 2006 9:49 pm
Jeff,

Consider (x-1)^2 > 4
which will mean (x-1)^2-4>0
((x-1)+2)((x-1)-2)>0 [using the identity a^2-b^2 =(a+b)(a-b)]
Simplifying,
(x+1)(x-3)>0
now for a product of two terms {(x+1),(x+3)} to be positive
either both x+1 and x-3 to be postive which is possible only when x>3
or both x+1 and x-3 to be negative which is possible only when x<-1

so we can safely conclude that (x-1)^2 > 4 will mean x>3 or x<-1
moving on similar lines we can solve the other inequality also ...
Revert back to me if you have any doubts on this.

As promised, answers in 3 days of time
Last edited by ajith on Mon Oct 30, 2006 9:54 pm, edited 2 times in total.

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

by ajith » Mon Oct 30, 2006 9:51 pm
rajs.kumar wrote:E.

First case leads to x > 3 or x > -1 => insufficient
Second case leads to x > 5 or x > -1 => insufficient

Both together is still inconclusive x could be a positive number greater or less or equal to 3.
I think you have made a mistake there rajs.kumar,

is it x > -1 or x<-1 ?

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

Re: DS question a Day

by ajith » Mon Oct 30, 2006 10:41 pm
DS002

What is the value of (2a+b)/(a+b)?

(1) 3a/(a+b) = 7
(2) a+b = 3

A) 1 alone b not sufficient
B) 2 alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient



Answers In 3 days of time,

Hereafter, when you reply , either quote the question or reply with the question number as there can be overlap.
Thanks,
Ajith

User avatar
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Wed Jul 12, 2006 3:13 pm
Followed by:4 members

Re: DS question a Day

by limits660 » Tue Oct 31, 2006 6:53 am
ajith wrote:Jeff,

Consider (x-1)^2 > 4
which will mean (x-1)^2-4>0
((x-1)+2)((x-1)-2)>0 [using the identity a^2-b^2 =(a+b)(a-b)]
Simplifying,
(x+1)(x-3)>0
now for a product of two terms {(x+1),(x+3)} to be positive
either both x+1 and x-3 to be postive which is possible only when x>3
or both x+1 and x-3 to be negative which is possible only when x<-1

so we can safely conclude that (x-1)^2 > 4 will mean x>3 or x<-1
moving on similar lines we can solve the other inequality also ...
Revert back to me if you have any doubts on this.

As promised, answers in 3 days of time
Yes, i see it now. Thanks very much on the details :D
-
Jeff Sacco
www.jeffsacco.ca

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

Re: DS question a Day

by ajith » Wed Nov 01, 2006 8:17 pm
ajith wrote:DS001

If x is positive, is x>3?

a) (x-1)^2 > 4
b) (x-2)^2 > 9

A) a alone b not sufficient
B) b alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient



Answers In 3 days of time

3 days are over!


When we solve a we get x>3 or x<-1(refer the above post for explanation)
since x is positive , x>3

So a is sufficient to answer

now conisdering b

(x-2)^2 > 9
=>(x-2+3)(x-2-3)>0
upon solving which we get x>5 or x<-1
since x is positive , x>5

So b is sufficient to answer

so the answer is D. Both alone are sufficient
Always borrow money from a pessimist, he doesn't expect to be paid back.

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

DS003

by ajith » Wed Nov 01, 2006 8:29 pm
DS003

How many people are in the second car in a line of three cars?

1. The total number of people in the three cars is one more than the total number of people in the first and third car.

2. There are a total of 7 people in the three cars.

A) 1 alone b not sufficient
B) 2 alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient

:roll:
Always borrow money from a pessimist, he doesn't expect to be paid back.

Senior | Next Rank: 100 Posts
Posts: 87
Joined: Fri Jun 09, 2006 2:47 am
Thanked: 2 times

by rajs.kumar » Thu Nov 02, 2006 1:41 am
ajith wrote:
rajs.kumar wrote:E.

First case leads to x > 3 or x > -1 => insufficient
Second case leads to x > 5 or x > -1 => insufficient

Both together is still inconclusive x could be a positive number greater or less or equal to 3.
I think you have made a mistake there rajs.kumar,

is it x > -1 or x<-1 ?
I figured where I went wrong. thanks.

(x-1) ^ 2 > 4 => x-1 > 2 or x-1 < -2 and I missed the x is positive. Overlooked.
Last edited by rajs.kumar on Fri Nov 03, 2006 1:20 am, edited 1 time in total.

Senior | Next Rank: 100 Posts
Posts: 87
Joined: Fri Jun 09, 2006 2:47 am
Thanked: 2 times

Re: DS question a Day

by rajs.kumar » Thu Nov 02, 2006 5:12 am
ajith wrote:DS002

What is the value of (2a+b)/(a+b)?

(1) 3a/(a+b) = 7
(2) a+b = 3

A) 1 alone b not sufficient
B) 2 alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient



Answers In 3 days of time,

Hereafter, when you reply , either quote the question or reply with the question number as there can be overlap.
Thanks,
Ajith
x = a+b => (a + x)/x =

1. 3a/x = 7 => a = 7x/3

7x/3/x + 1 => suff

2. a+b = 3 = x

(a+3)/3 => insuff

Answer is A.

Senior | Next Rank: 100 Posts
Posts: 87
Joined: Fri Jun 09, 2006 2:47 am
Thanked: 2 times

Re: DS003

by rajs.kumar » Thu Nov 02, 2006 5:16 am
ajith wrote:DS003

How many people are in the second car in a line of three cars?

1. The total number of people in the three cars is one more than the total number of people in the first and third car.

2. There are a total of 7 people in the three cars.

A) 1 alone b not sufficient
B) 2 alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient

:roll:
Answer is A.

A+B+C = A+C+1 => suff

User avatar
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Wed Jul 12, 2006 3:13 pm
Followed by:4 members

Re: DS003

by limits660 » Thu Nov 02, 2006 6:15 am
ajith wrote:DS003

How many people are in the second car in a line of three cars?

1. The total number of people in the three cars is one more than the total number of people in the first and third car.

2. There are a total of 7 people in the three cars.

A) 1 alone b not sufficient
B) 2 alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient

:roll:
A baby! :D

Im pretty sure I got this one :D
-
Jeff Sacco
www.jeffsacco.ca

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

DS002 answers

by ajith » Fri Nov 03, 2006 12:06 am
DS002

What is the value of (2a+b)/(a+b)?

(1) 3a/(a+b) = 7
(2) a+b = 3

A) 1 alone b not sufficient
B) 2 alone a not sufficient
C) both together but not alone sufficient
D) each alone sufficient
E) together not sufficient



Ans:
3a/(a+b)=7
=>a/a+b=7/3
=> 1+a/a+b=1+7/3
=>2a+b/a+b=10/7

so 1 is sufficient

it's evident that 2 is not by itself sufficient
so

A
Always borrow money from a pessimist, he doesn't expect to be paid back.

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

DS004

by ajith » Fri Nov 03, 2006 12:26 am
DS004

is |x+y| = 5?

1) |x| = 3
2) |y| = 2
Always borrow money from a pessimist, he doesn't expect to be paid back.