Data Sufficiency

is x> Y^2

1) x> y+5

2) x^2 - y^2 =0

venmic wrote:is x> Y^2

1) x> y+5

2) x^2 - y^2 =0

from Statement 1: X > y+5 ... X can be take varied values like -1 with y = -7..which is X < Y^2
also say x = 5 and y = -2 which is X > Y^2!,
Not sufficient!

from statement 2: x^2 - y^2 = 0, say x = 2 and y = -2... which is X < Y^2!
Also, x = 1/2, y = 1/2 ...which leads to X > Y^2!
so, it's not suffcient.

combine 2 statements:
1) X > Y + 5 2) X^2 - Y^2 = 0.
suitable values for the above 2 conditions are: X = + or - Y values!
x = 3 and Y = -3, or x = 4 or -4 , or 5 or -5...etc
except X = 1 and Y = -1 or X = 2 and Y = -2 ..also no fraction values suitable for the 2 condition!

finally, for all the satisfied values , the given expression will always be X < Y^2!

Hence Ans will be C!

n@resh wrote:

venmic wrote:is x> Y^2

1) x> y+5

2) x^2 - y^2 =0

from Statement 1: X > y+5 ... X can be take varied values like -1 with y = -7..which is X < Y^2
also say x = 5 and y = -2 which is X > Y^2!,
Not sufficient!

from statement 2: x^2 - y^2 = 0, say x = 2 and y = -2... which is X < Y^2!
Also, x = 1/2, y = 1/2 ...which leads to X > Y^2!
so, it's not suffcient.

combine 2 statements:
1) X > Y + 5 2) X^2 - Y^2 = 0.
suitable values for the above 2 conditions are: X = + or - Y values!
x = 3 and Y = -3, or x = 4 or -4 , or 5 or -5...etc
except X = 1 and Y = -1 or X = 2 and Y = -2 ..also no fraction values suitable for the 2 condition!

finally, for all the satisfied values , the given expression will always be X < Y^2!

Hence Ans will be C!

for second if we do like this

X^2 - Y^2 = 0.
X^2= Y^2 -> X=+/-Y ....is this a correct approach ?

yes

Yes arpana thats a correct approach,

Statement 1 x> y+5

Gives a wide variety of nos which sometimes satisfy and sometimes dosent..

Statement 2 x^2 - y^2 =0

Again give a +- answer
(x+y)(x-y)
x=y
x= -y
Not sufficient

If we conclude both answers we can answer .....

Hence C