Data Sufficiency

Can anyone help with this?

Does x=3?

(1) (x-3)(y-1)=0

(2) (x-3)^2+(y-1)^2=0

dunnec3 wrote:Can anyone help with this?

Does x=3?

(1) (x-3)(y-1)=0

(2) (x-3)^2+(y-1)^2=0

Statement 1: Either x = 3 or y = 1. If y = 1, x can be any number. Not sufficient.

Statement 2: (x-3)^2 and (y-1)^2 are both non-negative numbers - a number squared cannot be negative. So the only way they can sum to 0 is if they're both equal to 0. The only way (x-3)^2 can equal 0 is if x = 3. So 2 alone is sufficient. Answer is B