Can anyone help with this?
Does x=3?
(1) (x-3)(y-1)=0
(2) (x-3)^2+(y-1)^2=0
DS Algebra Q
This topic has expert replies
- DavidG@VeritasPrep
- Legendary Member
- Posts: 2663
- Joined: Wed Jan 14, 2015 8:25 am
- Location: Boston, MA
- Thanked: 1153 times
- Followed by:128 members
- GMAT Score:770
Statement 1: Either x = 3 or y = 1. If y = 1, x can be any number. Not sufficient.dunnec3 wrote:Can anyone help with this?
Does x=3?
(1) (x-3)(y-1)=0
(2) (x-3)^2+(y-1)^2=0
Statement 2: (x-3)^2 and (y-1)^2 are both non-negative numbers - a number squared cannot be negative. So the only way they can sum to 0 is if they're both equal to 0. The only way (x-3)^2 can equal 0 is if x = 3. So 2 alone is sufficient. Answer is B