Data Sufficiency

if n and q are different integers, does n=0?

1) 3nq + q^2 = (n+q)^2
2) q[(2-n) - (2+n)] = 0

Answer says D!

i see 1) as nq=n^2, so n=0 since n and q are different. so 1) is ok
for 2 i get q(-2n) = 0 so either q =0 and n= anything else or n =0 and q is anything else .. so 2 is not sufficient. I would pick A....
any ideas?

victorzachev wrote:if n and q are different integers, does n=0?

1) 3nq + q^2 = (n+q)^2
2) q[(2-n) - (2+n)] = 0

Answer says D!

i see 1) as nq=n^2, so n=0 since n and q are different. so 1) is ok
for 2 i get q(-2n) = 0 so either q =0 and n= anything else or n =0 and q is anything else .. so 2 is not sufficient. I would pick A....
any ideas?

I would go with A too .. from statement 2 it is clear that q or n could be 0 .. no definite answer .. so insufficient.