franciskyle wrote:For this one, I would start with deciding which answers gave a remainder of 3 when divided by 5 (the units digit would have to be either 3 or 8 because to be divisible by the units would have to be 0 or 5... add 3 to get 3 and 8 respectively). That leaves us with B & E.
A quick look and you know that 4 goes into 33 eight times with a remainder of 1. Therefore E.
Ah, note that the correct answer shouldn't give the same remainders that are mentioned in the question. The question asks for the
sum of two different numbers with certain remainders. We know each of those two numbers will have a remainder of 3 when divided by 5; when we add those two numbers we should now have a remainder of 1 when we divide by 5 (because 3+3 has a remainder of 1). We also want a number with a remainder of 2 when divided by 4, since the two numbers we're adding give a remainder of 1 when divided by 4.
Still, two answer choices remain, unfortunately, so some other method would be needed to choose between 46 and 86.
