At a certain university, the ratio of the number of teaching assistants to the number of students in any Course must always be greater than 3:80. at this university, what is the maximum number of students Possible in a course that has 5 teaching assistants?
130
131
132
133
134
please show the calculation
Ratio
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you can also cross multiply the ratio's to find out which one will be the maximum value. For example:
Let's take 131 -
5 / 131 > 3 / 80 - now cross multliply
80 * 5 > 131 * 3 - true
Let's take 131 -
5 / 131 > 3 / 80 - now cross multliply
80 * 5 > 131 * 3 - true
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I would go with 133 as well, its asking maximum number of students so 130-133 satisfy ratio > 3/80, 133 being maximum while for 134 ratio is less
**typing mistake
**typing mistake
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Greater ratio means more teachers , less students. So students cannot exceed 133.33.hongwang9703 wrote:must always be greater than 3:80
id go with 134,
So 133 is correct.
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We are given that the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80, and we need to determine the maximum number of students possible in a course that has 5 teaching assistants. Let's use the following formula, in which t = 5 = the number of teaching assistants and s = the number of students.hpgmat wrote:At a certain university, the ratio of the number of teaching assistants to the number of students in any Course must always be greater than 3:80. at this university, what is the maximum number of students Possible in a course that has 5 teaching assistants?
130
131
132
133
134
t/s> 3/80
5/s > 3/80
400 > 3s
400/3 > s
133.33 > s
Since s must be a whole number, the largest possible value of s is 133.
Answer: D
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