I came across a question that asks about decimal equivalent, I couldn't figure it out what the question is asking for
Can anybody give a pointer on this?
Q: Which of the following fractions has a decimal equivalent that terminates?
49/224
22/189
37/196
25/513
17/175
the answer is 49/224, but i donno why..
decimal equivalent that terminates?
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If Q's like this are representative of the original GMAT, 2 min is not going to be enough.
Think about the opposite of termination. Recurring. Recurring decimals are the ones which do not end. some thing like .3333333 or .67777777777 and on
49/224= 7/32= .2175 and it ends there.
Glad the answer is A and not E.
Guru's
Any easy way of finding out if a fraction is going to yield a recurring decimal or terminating decimal. terminating decimal?? Is that a valid mathematical term? I have never heard of it, even though I could understand what the Q is trying to get at.
Think about the opposite of termination. Recurring. Recurring decimals are the ones which do not end. some thing like .3333333 or .67777777777 and on
49/224= 7/32= .2175 and it ends there.
Glad the answer is A and not E.
Guru's
Any easy way of finding out if a fraction is going to yield a recurring decimal or terminating decimal. terminating decimal?? Is that a valid mathematical term? I have never heard of it, even though I could understand what the Q is trying to get at.
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Also found this on MGMAT forums
For fraction p/q to be a terminating decimal, the numerator must be an integer and the denominator must be an integer that can be expressed in the form of 2^x 5^y where x and y are nonnegative integers. (Any integer divided by a power of 2 or 5 will result in a terminating decimal.)
How ever 224 cannot be expressed in 2^x 5^y form. 224 comes down to 2^5 X 7^1
For fraction p/q to be a terminating decimal, the numerator must be an integer and the denominator must be an integer that can be expressed in the form of 2^x 5^y where x and y are nonnegative integers. (Any integer divided by a power of 2 or 5 will result in a terminating decimal.)
How ever 224 cannot be expressed in 2^x 5^y form. 224 comes down to 2^5 X 7^1
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That's true, what you've quoted above, except it's incomplete. In any terminating decimal question like the above:chidcguy wrote:Also found this on MGMAT forums
For fraction p/q to be a terminating decimal, the numerator must be an integer and the denominator must be an integer that can be expressed in the form of 2^x 5^y where x and y are nonnegative integers. (Any integer divided by a power of 2 or 5 will result in a terminating decimal.)
How ever 224 cannot be expressed in 2^x 5^y form. 224 comes down to 2^5 X 7^1
1. Make sure you reduce your fractions first.
2. Then prime factorize the denominators. If you see any prime besides 2 or 5, the decimal is recurring. If you only see 2s and/or 5s, it terminates.
So, in the text I quoted above, while it's true that 224 is divisible by 7, that 7 cancels with the 49 in the numerator- you need to reduce the fraction first.
You can see why step 2. above works- let's use the example answer choice A from the question:
49/224 = 7/32 = 7/2^5. Now multiply numerator and denominator by 5^5 so you have equal powers on 2 and 5 in the denominator:
(7/2^5)*(5^5/5^5) = 7*5^5/(2^5 * 5^5) = (7*5^5)/(10)^5
We have a fraction with a denominator of 100,000, and it's clear when you have a power of 10 in the denominator you get a terminating decimal. There's no need to multiply out the numerator, but if you do you can see exactly what decimal you get:
(7*5^5)/(10)^5 = 21,875/100,000 = 0.21875
Long story short, if your denominator is such that you could make a power of 10, you can get a terminating decimal. That is, the only primes you want to see in the denominator are 2 and/or 5 (***after you've reduced the fraction***). If there's any other prime down there, you have a recurring (infinite) decimal.